Answer:
The force is
Explanation:
The moment of Inertia I is mathematically evaluated as
Substituting for M(Mass of the wheel) and for (Radius of wheel)
The torque on the wheel due to net force is mathematically represented as
Substituting 135 N for (Force acting on sprocket), for (radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now
This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of and this torque can also be represented mathematically as
Now equating the two equation for torque
Making F the subject
Substituting values
Answer:
The acceleration required by the rocket in order to have a zero speed on touchdown is 19.96m/s²
The rocket's motion for analysis sake is divided into two phases.
Phase 1: the free fall motion of the rocket from the height 2.59*102m to a height 86.9m
Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 86.9m to the point of touchdown y = 0m.
Explanation:
The initial velocity of the rocket is 0m/s when it started falling from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.
The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.
The detailed step by step solution to the problems can be found in the attachment below.
Thank you and I hope this solution is helpful to you. Good luck.
Transverse waves. Direction of vibration of the particles is at right angles to direction of movement.
Answer:
Ep = 117600 J
Explanation:
Data:
- Mass (m) = 600 kg
- Height (h) = 20 m
- Gravity (g) = 9.8 m/s²
- Potential Energy (Ep) = ?
Use formula:
Replace:
- Ep = 600 kg * 9.8 m/s² * 20 m
Multiply operations, and units:
What is the potential energy?
The potential energy is <u>117600 Joules.</u>
Explanation:
The given data is as follows.
Electric potential energy () = ?
Formula to calculate electric potential energy is as follows.
=
=
Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is .