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Illusion [34]
2 years ago
8

A 0.3 g mosquito is flying toward a girl with a speed of 4.5 mph. Just before landing on the girl, the fly is swatted straight b

ack at a speed of 12 mph. If the fly swatter and the fly were in contact for 0.2 s, what is the force that was exerted on the fly
Physics
1 answer:
luda_lava [24]2 years ago
5 0

Answer:

1.1x10^-2N

Explanation:

We have the change in momentum as

P = 0.3(4.5+12)g.mph

= 0.3x0.447x(4.5+12)x10^-3

Then the force that is exerted will be

F = p/∆t

∆t = 0.2

= 0.3x0.447x(4.5+12)x10^-3/0.2

= 0.1341x16.5x10^-3/0.2

= 1.1x10^-2

Therefore the force that was exerted is equal to 1.1x10^-2

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Given that: = 2i + 9j +3k and = -i – 4k . Find
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How is the earths surface shaped by weathering, erosion, and deposition. Give and example of each
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4 0
3 years ago
A 325 g iron bucket contains 527 g of water, both at 21.6°C. A 855 g piece of hot steel (T = 352 degrees Celsius) is added to bu
Neporo4naja [7]

Answer:

T = 18.63 ^oC

Explanation:

As we know that heat given by the hot piece of iron = heat absorbed by water + ice

As we know that

c_{iron} = 0.450 J/g ^oC

also we have

c_{ice} = 2050 J/kg ^oC

now we have

325(0.450)(T-21.6) + 0.527(4186)(T - 21.6) + 0.295(2050)(0 + 22.2) + (0.295)(335000) + 0.295(4186)(T - 0) = 855(0.450)(352 - T)

146.25T - 3159 + 2206T - 47650 + 13425.45 + 98825 + 1234.87T = 135432 - 384.75 T

3971.87 T = 73990.55

T = 18.63 ^oC

3 0
3 years ago
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