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Nata [24]
3 years ago
14

The Electrons in a beam are moving at 2.7x108 m/s in an electric field of 16000 N/C. What value must the magnetic field have if

the electrons pass through the crossed fields undeflected?
Physics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

B = 0.07 mT

Explanation:

q = 1.6x10^-19 coulombs

for the electron to pass through the field undeflected the magnetic force acting on it must equal the electrical force due to the electric field

electric force = Eq = 16000 * 1.6x10^-19 newtons

magnetic force = qvB = 1.6x10^-19 * 2.7x10^8 * B

16000 * 1.6x10^-19 = 1.6x10^-19 * 2.7x10^8 * B

B = 0.07 mT (milli tesla)

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A 84-kg man stands on a bathroom scale inside an elevator. the scale measures in units of newtons. (a) the elevator accelerates
valentina_108 [34]

Answer:

  94 kg

Explanation:

The mass registered by the scale is based on the assumption that the force applied is due entirely to gravity. If the force is greater, then the indicated mass will be greater.

__

<h3>how many g's</h3>

As a fraction of the acceleration of gravity, the elevator's acceleration is ...

  (1.2 m/s²)/(9.8 m/s²) ≈ 6/49

<h3>net force</h3>

The force required to produce a given acceleration is found by the formula ...

  F = ma . . . . . . . force on mass m to produce acceleration 'a'

When the man is stationary on the scale, the upward force it supplies is balanced by the downward force on the man due to gravity. The force and the mass are proportional, and the constant of proportionality (the acceleration due to gravity) is used to calibrate the scale. More force is thus translated to a higher mass reading.

Since the man's net acceleration is upward at the rate of 6/49×g, the total force applied by the scale is (1 +6/49) = 55/49 times as great as when the man is stationary. This greater force gets translated to a greater mass reading.

The force is equivalent to what would be required to support a stationary man with a mass of ...

  (84 kg)(55/49) = 94 2/7 kg

The scale would read about 94 kg during the upward acceleration period.

3 0
2 years ago
Sarah added sugar to her iced tea, but it is not dissolving very quickly. Which can Sarah do to make the sugar dissolve faster?
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5 0
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How do I figure out the GPE of an object on the ground? question 28.
Leona [35]
In this scenario, only conservative force is acting on the ice-cream hence energy is conserved.
Now, you know that ice-cream was held at a height of 1.75 m from ground. Taking ground( h= 0 meters) as reference,

Total energy of ice-cream before it fell = Total energy after it reached the ground.

Once ice-cream falls, all its GPE is converted into kinetic energy. Kinetic energy will be maximum just before it hits the ground. And since ice-cream is inelastic substance, it will come to at rest. That is, its GPE will be zero on the ground
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3 years ago
Why is money management important ?how would you rate your own money management ?
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4 0
3 years ago
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
Tju [1.3M]

Answer:

v = 2.85 m/s

Explanation:

By the law of similarity of the triangle we can say

\frac{height\: of\: man}{distance\: of \: man\: from \: spotlight} = \frac{height \:of \:image}{distance\: of \:wall\: from\: spotlight}

here we know that

height of man = 2 m

let the distance of man from spotlight = x

distance of wall from spotlight = 12 m

height of image is let say "y"

so we will have

\frac{2}{x} = \frac{y}{12}

y = \frac{24}{x}

now we have

\frac{dy}{dt} = \frac{24}{x^2}\frac{dx}{dt}

here we know

\frac{dx}{dt} = speed = 1.9 m/s

x = 4 m

now we have

\frac{dy}{dt} = \frac{24}{4^2}(1.9)

v = 2.85 m/s

8 0
4 years ago
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