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nadezda [96]
3 years ago
14

What is BEST to say about a runner who is running at a constant velocity? A. Their acceleration is positive. B. Their accelerati

on is negative. C. Their acceleration is zero. D. Their acceleration cannot be determined.
Physics
2 answers:
Leto [7]3 years ago
4 0
<span>The question is asking us what is BEST to say about a runner who is running at a constant velocity? A constant velocity (=speed) means that they are not getting faster or slower - they are running exactly as fast all the time. This meanst that their speed does not change, so their change of speed is equal to 0. A change of speed is called acceleration so their C. Their acceleration is zero. - C is the correct answer. </span>
IRINA_888 [86]3 years ago
3 0

the correct answer is C.


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Answer:

35.3 N

Explanation:

U = 0, V = 0.61 m/s, s = 0.39 m

Let a be the acceleration.

Use third equation of motion

V^2 = u^2 + 2 as

0.61 × 0.61 = 0 + 2 × a × 0.39

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3 years ago
Light travels faster in warmer air. On a sunny day, the sun can heat a road and create a layer of hot air above it. Let's model
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Answer:

Explanation:

If we assume there is a sharp boundary between the two masses of air, there will be a refraction. The refractive index of each medium will depend on the relative speeds of light.

n = c / v

If light travels faster in warmer air, it will have a lower refractive index

nh < nc

Snell's law of refraction relates angles of incidence and refracted with the indexes of refraction:

n1 * sin(θ1) = n2 * sin(θ2)

sin(θ2) = sin(θ1) * n1/n2

If blue light from the sky passing through the hot air will cross to the cold air, then

n1 = nh

n2 = nc

Then:

n1 < n2

So:

n1/n2 < 1

The refracted light will come into the cold air at angle θ2 wich will be smaller than θ1, so the light is bent upwards, creating the appearance of water in the distance, which is actually a mirror image of the sky.

6 0
3 years ago
Definition of continental polar
kipiarov [429]

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8 0
3 years ago
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3 years ago
Consider two ideal gases, A and B, at the same temperature. The rms speed of the molecules of gas A is twice that ofgas B. How d
katen-ka-za [31]

The rms speed of the molecules of gas A is twice that of gas B. The molecular mass of A is one fourth to that of B.

Answer: Option B

<u>Explanation:</u>

Measuring the speed of particles at a given point in time results in a large distribution of values. Some molecules can move very slowly, others very fast, and because they are still moving in different directions, the speeds may be zero. (Velocity, vector quantity that corresponds to the speed and direction of the molecule.)

To correctly estimate the average velocity, you must take the squares of the mean velocity and take the square root of this value. This is known as the root mean square (rms) velocity and is shown as follows:

                 V_{r m s}=\sqrt{\frac{3 R T}{M}}

Where,

M – Gas’s molar mass

R – Molar mass constant

T – Temperature (in Kelvin)

Given data is rms speed for gas molecule A is twice that of gas molecule B. So,

                 \left(V_{r m s}\right)_{A}=2\left(V_{r m s}\right)_{B}

Therefore, equating the molecule’s rms speed formula for both A and B,

                  \sqrt{\frac{3 R T}{M_{A}}}=2(\sqrt{\frac{3 R T}{M_{B}}})

On squaring both sides, we get,

                 \frac{3 R T}{M_{A}}=4\left(\frac{3 R T}{M_{B}}\right)

By solving the above equations, we get,

                 M_{A}=\frac{M_{B}}{4}

8 0
3 years ago
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