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nadezda [96]
3 years ago
14

What is BEST to say about a runner who is running at a constant velocity? A. Their acceleration is positive. B. Their accelerati

on is negative. C. Their acceleration is zero. D. Their acceleration cannot be determined.
Physics
2 answers:
Leto [7]3 years ago
4 0
<span>The question is asking us what is BEST to say about a runner who is running at a constant velocity? A constant velocity (=speed) means that they are not getting faster or slower - they are running exactly as fast all the time. This meanst that their speed does not change, so their change of speed is equal to 0. A change of speed is called acceleration so their C. Their acceleration is zero. - C is the correct answer. </span>
IRINA_888 [86]3 years ago
3 0

the correct answer is C.


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Klio2033 [76]
  • Frequency=v=4.75×10^12Hz
  • Wavelength=?

We know

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\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}

\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m

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3 years ago
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Answer:

The correct option is;

a- sea surface temperature anomaly, in degrees Celsius

Explanation:

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6 0
3 years ago
Amir pitches a baseball at an initial height of 6 feet with a velocity of 73 feet per second. this can be represented by the fun
Romashka [77]

The values of t are <u>4.643 second</u> for the function H(t)=-16t^2+73t+6

What is batter misses?

An out in baseball happens when the umpire declares a batter or baserunner out. A hitter or runner who is out is no longer able to score runs and must go back to the dugout until their subsequent turn at bat. The batting team's turn is over after three outs are recorded in a half-inning.

In order to signal an out, umpires typically make a fist with one hand and then flex that arm, either upward on pop flies or forward on regular plays at first base. To indicate a called strikeout, home plate umpires frequently use a "punch-out" action.When a batter is struck by a pitched ball without making a swing at it, it is referred to as a hit-by-pitch. He consequently gets first base.

We have been given that

s = 6 feet

v = 73 feet per second

Substituting these values in the formula H(t)=-16t^2+vt+s

H(t)=-16t^2+73t+6

When the ball hits the ground, the height becomes zero. Thus, H(t)=0

-16t^2+73t+6=0

We solve the equation using quadratic formula x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

Substituting the values a=-16, b= 73, c=6

t_{1,2}=\frac{-73 \pm \sqrt{(73)^2-4(-16)(6)}}{2(-16)}\\\Rightarrow t_{1,2}=\frac{-73 \pm \sqrt{5713}}{2(-16)}\\\Rightarrow t_{1,2}=-0.081, 4.643

Learn more about the batter misses with the help of the given link:

brainly.com/question/19475098

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8 0
1 year ago
In the diagram, which is demonstrated by arrow 1? A. liquid water evaporating from the surface to the atmosphere B. water vapor
Shkiper50 [21]
I think D. liquid water moving along the surfac

6 0
3 years ago
A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of
GREYUIT [131]

Answer:

a=190\ m/s^2

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2

So, the acceleration of the hockey puck is 190\ m/s^2.

5 0
3 years ago
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