250kg
would have momentum that is being caried by the impact of the trow
In order to balance the stick on the pivot, the total "moments" must be equal on both sides. A "moment" is (a weight) x (its distance from the center).
for the 5N weight: Moment = (5N) x (3 cm) = 15 N-cm
for the 12N weight: Moment = (12N) x (5 cm) = 60 N-cm
Sum of the moments trying to pull the stick down on that side = 75 N-cm
Whatever we hang on the other side has to provide a moment of 75 N-cm in the other direction. We have a 25N weight. Where should we hang it ?
(25N) x (distance from the pivot) = 75 N-cm
Distance from the pivot = (75 N-cm) / (25 N)
<em>Distance from the pivot = 3 cm </em>
F = ma = -kx
a = 9.81 m/s²
k = 3430 N/m
m = 70 kg
x = - ma/ k = 0.2m
Answer: W = 1.5 J
Explanation: Work is the product of force and distance. It can be expressed in the following formula W = Fd.
W = Fd
= 5 N ( 0.3 M )
= 1.5 J
