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2 years ago

1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?

Chemistry

1 answer:

faltersainse [42]2 years ago

3 0

Answer:

0.01 moles of SrCO₃

Explanation:

In this excersise we need to propose the reaction:

K₂CO₃ + Sr(NO₃)₂ → 2KNO₃ + SrCO₃

As we only have data about the potassium carbonate we assume the strontium nitrite as the excess reactant.

1 mol of K₂CO₃ react to 1 mol of Sr(NO₃)₂ in order to produce 2 moles of potassium nitrite and 1 mol of strontium carbonate.

Ratio is 1:1. In conclussion,

0.01 mol of K₂CO₃ must produce 0.01 moles of SrCO₃

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1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?​

1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?