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2 years ago

What are the products of the balanced equation for the combustion of C8H17OH ?

Chemistry

1 answer:

erastova [34]2 years ago

3 0

C8H17OH + 12O2 —> 8CO2 + 9H2O

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CCC Patterns Changes in the state of matter (solid, liquid, gas) are the result of different energy levels at the molecular leve

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3 years ago

How much aluminum oxide and how much carbon are needed to prepare 573 g of aluminum by the balanced chemical reaction (below) if

yawa3891 [41]

Answer:

1387.2g of Al2O3

Explanation:

The number of moles of aluminum oxide required to give the actual yield is obtained from the given mass of aluminum produced by the reaction. The percentage yield is used to obtain the theoretical yield of the aluminum. The number of moles produced theoretically can be used to calculate the amount of aluminum oxide required in moles and when we multiply the value obtained by the molar mass of aluminum oxide, we obtain the mass of aluminum oxide required.

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2 years ago

Read 2 more answers

How to solve 2=-log(x)

ch4aika [34]

First, you want to extract the negative from -log(x).

So now you have log(x) = -2

Now you have to use the property loga(x)=b is the same as x=a^2

So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.

Then you evaluate the negative square to 1/10^2

Answer is 1/100

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2 years ago

A form of carbon in which carbon atoms are arranged in a (n)__

abruzzese [7]

graphite is a form of carbon in which carbon atoms are arranged in a layer.

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3 years ago

Which buffer would be better able to hold a steady pH on the addition of strong acid, buffer 1 or buffer 2? Explain. Buffer 1: a

Talja [164]

Answer:

Buffer 1.

Explanation:

Ammonia is a weak base. It acts like a Bronsted-Lowry Base when it reacts with hydrogen ions.

$\rm NH_3\; (aq) + H^{+}\; (aq) \to {NH_4}^{+}\; (aq)$ .

$\rm NH_3$ gains one hydrogen ion to produce the ammonium ion $\rm {NH_4}^{+}$ . In other words, $\rm {NH_4}^{+}$ is the conjugate acid of the weak base $\rm NH_3$ .

Both buffer 1 and 2 include

the weak base ammonia $\rm NH_3$ , and
the conjugate acid of the weak base $\rm {NH_4}^{+}$ .

The ammonia $\rm NH_3$ in the solution will react with hydrogen ions as they are added to the solution:

$\rm NH_3\; (aq) + H^{+}\; (aq) \to {NH_4}^{+}\; (aq)$ .

There are more $\rm NH_3$ in the buffer 1 than in buffer 2. It will take more strong acid to react with the majority of $\rm NH_3$ in the solution. Conversely, the pH of buffer 1 will be more steady than that in buffer 2 when the same amount of acid has been added.

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3 years ago