Can a pressure change shift the equilibrium position in every reversible reaction? Explain

Write the balanced standard combustion reaction for the c5h7on3s2

AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0

3 years ago

The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding

kirza4 [7]

Answer: Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=\frac{Nhc}{\lambda}$

where,

$E$ = energy of the wave = 182 kJ/mol = 182000 J/mol

N = avogadro's number = $6.023\times 10^{23}$

h = plank constant = $6.6\times 10^{-34}Js^{-1}$

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of the wave = ?

Putting all the values:

$182000=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^8m/s}{\lambda}$

$\lambda=0.65\times 10^{-6}m=650nm$ $(1nm=10^{-9}m)$

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

5 0

3 years ago

Examine the equation.

Alisiya [41]

Explanation:

The reaction expression is given as;

2H₂ $_{g}$ + O₂ $_{g}$ → 2H₂O $_{l}$

From the balance reaction expression:

2 mole of hydrogen gas combines with 1 mole of oxygen gas on the reactant side;

This produces 2 mole of water on the product side of the expression.

The product is in liquid form.

This reaction is a synthesis reaction because a single product is formed from two reactants.

5 0

3 years ago

How do you balance this equation?

anyanavicka [17]

Answer:

HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O

The coefficients are: 1, 1, 1, 1, 1

Explanation:

_HC₂H₃O₂ + _NaHCO₃ —> _NaC₂H₃O₂ + _CO₂ + _H₂O

To balance an equation, we simply do a head count of the individual elements and ensure they are balanced on both side.

For the above equation, we shall balance it as :

HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O

Reactant:

H = 5

C = 3

O = 5

Na = 1

Product:

H = 5

C = 3

O = 5

Na = 1

From the above, we can see that each element is the same on both side of the equation. Thus the equation is already balanced

HC₂H₃O₂ + NaHCO₃ —> NaC₂H₃O₂ + CO₂ + H₂O

The coefficients are: 1, 1, 1, 1, 1

5 0

3 years ago

Have you guys ever felt love and then betrayed?

sukhopar [10]

Yes i know how you feel girl best of luck <3

5 0

3 years ago

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