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yulyashka [42]
4 years ago
11

Number of representative particles in 0.250 mol silver

Chemistry
2 answers:
Gnom [1K]4 years ago
5 0
<span>A mole is just a specific number = 6.022 x 10^23 {actually this is approximately the number}. So one mole of a particular thing is 6.022 x 10^23 of those things. In a 0.250 mole silver = 0.250 (6.022 x 10^23) silver = 1.506 x 10^23 silver.</span>
denis-greek [22]4 years ago
4 0

<u>Answer:</u> The number of representative particles in the given amount of silver are 1.506\times 10^{23}

<u>Explanation:</u>

We are given:

Moles of silver = 0.250 moles

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of atoms

So, 0.250 moles of silver will contain = (0.250\times 6.022\times 10^{23})=1.506\times 10^{23} number of atoms.

Hence, the number of representative particles in the given amount of silver are 1.506\times 10^{23}

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Density is the mass of compound divided by its volume can be shown as follows:

d = 0.5 g /mL = m /V = m /40 = 0.5

m = 20 g

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As, 10 inches of rain will produce 11 inches of ice as the volume of ice is bigger than rain water.

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4 0
3 years ago
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

8 0
3 years ago
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The change of liquid into solid is the freezing point. The melting point is more than the freezing point in certain cases of mixtures for certain organic compounds like fats. As soon as the mixture freezes it becomes solid and which results in change in the composition from the liquid and solid in this way the it drastically reduces the freezing point. The melting point gets higher due to the pressure. This happens due to the release of heat of which results in the rise of temperature to the freezing point .Also the reaction of elements with oxygen which leads to formation of new substance is also an chemical property

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D. Add base
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