Construct a three-step synthesis of 3-bromocyclopentene from cyclopentane. Drag the appropriate items into the bins. Note that e
ach bin should hold only one item
1 answer:
Answer:
How about this?
Explanation:
(1) Halogenation of an alkane
Reaction with Br₂ in the presence of UV light to give bromocyclopentane.
(2) Dehydrohalogenation
Reaction with hot alcoholic KOH to give cyclopentene.
(3) Allylic bromination
Reaction with N-bromosuccinimide and a drop of HBr(aq) gives
3-bromocyclopentene.
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Answer:
20 g Ag
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Using Dimensional Analysis
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
Explanation:
<u>Step 1: Define</u>
[RxN] Cu (s) + AgNO₃ (aq) → CuNO₃ (aq) + Ag (s)
[Given] 10 g Cu
<u>Step 2: Identify Conversions</u>
[RxN] 1 mol Cu = 1 mol Ag
Molar Mass of Cu - 63.55 g/mol
Molar Mass of Ag - 197.87 g/mol
<u>Step 3: Stoichiometry</u>
<u /> = 16.974 g Ag
<u>Step 4: Check</u>
<em>We are given 1 sig fig. Follow sig fig rules and round.</em>
16.974 g Ag ≈ 20 g Ag
Answer: will have a greater partial charge.
Explanation:
A polar covalent bond is defined as the bond which is formed when there is a low difference of electronegativities between the atoms, thus resulting in charge difference. Example:
Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms and thus there is no charge difference. Example:
Ionic bond is formed when there is complete transfer of electron from a highly electropositive metal to a highly electronegative non metal. The electronegative difference between the elements is high. The charges on cation and anion neutralise each other. Example:
Thus as will have greater partial charge.
Answer: 9.9 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of
b) moles of
According to stoichiometry :
1 mole of combine with 1 mole of
Thus 0.33 mole of will combine with =
mole of
Thus is the limiting reagent as it limits the formation of product.
As 1 mole of give = 1 mole of
Thus 0.33 moles of give =
of
Mass of
Thus theoretical yield (g) of produced by the reaction is 9.9 grams