Construct a three-step synthesis of 3-bromocyclopentene from cyclopentane. Drag the appropriate items into the bins. Note that e
ach bin should hold only one item
1 answer:
Answer:
How about this?
Explanation:
(1) Halogenation of an alkane
Reaction with Br₂ in the presence of UV light to give bromocyclopentane.
(2) Dehydrohalogenation
Reaction with hot alcoholic KOH to give cyclopentene.
(3) Allylic bromination
Reaction with N-bromosuccinimide and a drop of HBr(aq) gives
3-bromocyclopentene.
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The formula for mole fraction is:
-(1)
The solubility of oxygen gas = 1.0 mmol/L (given)
1.0 mmol/L means 1.0 mmol are present in 1 L.
Converting mmol to mol:
So, moles of oxygen = 0.001 mol
For moles of water:
1 L of water = 1000 mL of water
Since, the density of water is 1.0 g/mL.
So, the mass of water is 1000 g.
Molar mass of water = 18 g/mol.
Number of moles of water =
Substituting the values in formula (1):
Hence, the mole fraction is .
<u>Answer:</u> The number of moles of gas present is 0.276 moles
<u>Explanation:</u>
To calculate the number of moles of gas, we use the equation given by ideal gas:
PV = nRT
where,
P = Pressure of the gas = 725 mm Hg
V = Volume of the gas = 7.55 L
n = number of moles of gas = ?
R = Gas constant =
T = Temperature of the gas =
Putting values in above equation, we get:
Hence, the number of moles of gas present is 0.276 moles