Construct a three-step synthesis of 3-bromocyclopentene from cyclopentane. Drag the appropriate items into the bins. Note that e
ach bin should hold only one item
1 answer:
Answer:
How about this?
Explanation:
(1) Halogenation of an alkane
Reaction with Br₂ in the presence of UV light to give bromocyclopentane.
(2) Dehydrohalogenation
Reaction with hot alcoholic KOH to give cyclopentene.
(3) Allylic bromination
Reaction with N-bromosuccinimide and a drop of HBr(aq) gives
3-bromocyclopentene.
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Answer:
Benzoic acid is the stronger acid
Explanation:
Weak acids do not dissociate completely in the solution. They exists in equilibrium with their respective ions in the solution.
The extent of dissociation of the acid furnising hydrogen ions can be determined by using dissociation constant of acid ().
Thus for a weak acid, HA
The is:
The more the , the more the acid dissociates, the more the stronger is the acid.
Also,
is defined as the negative logarithm of
.
So, more the , less is the
and vice versa
All can be summed up as:
The less the value of , the more the
is and the more the acid dissociates and the more the stronger is the acid.
Given,
of acetic acid = 54.7
of benzoic acid = 54.2
of benzoic acid <
of acetic acid
So, benzoic acid is the stronger acid.