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DanielleElmas [232]
2 years ago
11

Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.

Chemistry
1 answer:
Varvara68 [4.7K]2 years ago
4 0

Answer:

2.52 g NaCl

Explanation:

(Step 1)

To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the given values into the equation and simplify to find moles.

136.9 mL / 1,000 = 0.1369 L

Molarity = moles / volume

0.315 M = moles / 0.1369 L

0.0431 = moles

(Step 2)

Now, you can use the molar mass to convert moles to grams.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

0.0431 moles NaCl           58.443 g
------------------------------  x  -------------------  =  2.52 g NaCl
                                            1 mole

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Answer:

8.10g of sodium succinate must be added and 247mL of 0.1M HCl adding enough water until make 500mL

Explanation:

<em>Succinic acid has a pKa₂ of 5.63</em>

To solve this question we must find the amount of sodium succinate and 0.1M HCl that we have to add using H-H equation:

pH = pKa + log [A-] / [HA]

5.64 = 5.63 + log [Na₂Succ.] / [HSucc⁺]

0.01 = log [Na₂Succ.] / [HSucc⁺]

1.0233 = [Na₂Succ.] / [HSucc⁺] <em>(1)</em>

As:

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Replacing (2) in (1):

1.0233 = 0.1M - [HSucc⁺] / [HSucc⁺]

1.0233[HSucc⁺] = 0.1M - [HSucc⁺]

2.033[HSucc⁺] = 0.1M

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Both [Na₂Succ⁺] and [HSucc⁺] ions comes from the same sodium succinate we have to find the moles of sodium succinate in 500mL of 0.1M. Then, based on the reaction:

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The moles of HCl added = Moles HSucc⁺ we need:

<em>Moles Na₂Succ:</em>

0.500L * (0.1mol/L) = 0.0500 moles

<em>Mass -Molar mass sodium succinate: 162.05g/mol-:</em>

0.0500mol * (162.05g/mol) = 8.10g of sodium succinate must be added

<em>Moles HCl:</em>

0.0494M * 0.500L = 0.0247 moles HCl * (1L / 0.1mol) = 0.247L =

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Answer:

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