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meriva
3 years ago
9

The main buffering agents in human blood are h2co3 and hco3. Explain how this buffering system will be able to maintain blood pH

at a steady level when a small amount of a generic acid HA ( with ions H+ and A-) is added
Chemistry
1 answer:
den301095 [7]3 years ago
6 0

Answer:

The base, HCO₃⁻ of the buffering system will neutralize the acid added forming H₂CO₃.

Explanation:

A buffer solution keeps the pH in a narrow range upon the addition of an acid or base. A buffer consists of a pair of a weak acid and its conjugate base, or vice versa, in a pair of a weak base and its conjugate acid. In the case of human blood, the acid is H₂CO₃ and its conjugate base is HCO₃⁻.

The buffering system of the human blood maintain blood pH at a steady level when a small amount of a generic acid HA is added in the following way:

HCO₃⁻ + HA  ⇄  H₂CO₃ + A⁻

The base, HCO₃⁻, will neutralize the acid added forming the H₂CO₃, which is already a component of the buffering system of the human blood. Thus, hydronium ions of the acid added are removed, preventing the pH of blood from becoming acidic.                

On the other hand, when a small amount of a generic base A⁻ is added the following reaction takes place:    

H₂CO₃ + A⁻  ⇄  HCO₃⁻ + HA

In this case, the acid H₂CO₃ will neutralize the base added to form the base HCO₃⁻, which is already a component of the buffering system. Thus, the base added are removed from the blood, preventing the pH of blood from becoming basic.  

Since, the acid or its conjugate base will react with the base or acid added, to neutralizing it and forming the species that conform the buffer solution, the pH is being maintained at a steady level.  

In the process above, the addition of a small amount of an acid or a base won't change in a significant way the concentrations of the two components of the buffering system. This buffering mechanism prevents the blood from becoming acidic or basic.  

                   

I hope it helps you!

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The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
blsea [12.9K]

Answer:

V=0.68L

Explanation:

For this question we can use

V1/T1 = V2/T2

where

V1 (initial volume )= 0.75 L

T1 (initial temperature in Kelvin)= 303.15

V2( final volume)= ?

T2 (final temperature in Kelvin)= 273.15

Now we must rearrange the equation to make V2 the subject

V2= (V1/T1) ×T2

V2=(0.75/303.15) ×273.15

V2=0.67577931717

V2= 0.68L

4 0
3 years ago
You have 0.5 L of air at 203 k in an expandable container at constant pressure. You heat the container to 273 k. What is the vol
Jobisdone [24]
You can use P1V1/T1 = P2V2/T2 but since pressure is constant is becomes V1/T1=V2/T2

V1=0.5 L
T1=203 K
T2=273 K
V2=unknown

0.5L/203 = V2/273
V2= 0.67 L so C

Hope this helps :)
4 0
4 years ago
What is the redox equation for sulphuric acid and magnesium ribbon
Wewaii [24]
Sulfuric acid: H_2SO_4_{(aq)}
Magnesium ribbon: Mg_(s)
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8 0
3 years ago
What is the density of a mineral with a mass of 41.2 g and a volume 8.2 cm3?
dezoksy [38]
Hey there!:

mass = 41.2 g

Volume = 8.2 cm³

Therefore:

D = m / V

D = 41.2 / 8.2

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4 0
4 years ago
Read 2 more answers
a solution of silver (i) nitrate and a solution of calcium bromate react and produce a splice precipitate of silver bromate
kykrilka [37]

Answer:

2 AgNO₃(aq) + Ca(BrO₃)₂(aq) ⇒ Ca(NO₃)₂(aq) + 2 AgBrO₃(s)

2 Ag⁺(aq) + 2 NO₃⁻(aq) + Ca²⁺(aq) + 2 BrO₃⁻(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq) + 2 AgBrO₃(s)

2 Ag⁺(aq) + 2 BrO₃⁻(aq) ⇒ 2 AgBrO₃(s)

Explanation:

The question is missing but I think it must be about the chemical equations.

Let's consider the molecular equation that occurs when a solution of silver nitrate and a solution of calcium bromate react.

2 AgNO₃(aq) + Ca(BrO₃)₂(aq) ⇒ Ca(NO₃)₂(aq) + 2 AgBrO₃(s)

The complete ionic equation includes all the ions and the insoluble species.

2 Ag⁺(aq) + 2 NO₃⁻(aq) + Ca²⁺(aq) + 2 BrO₃⁻(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq) + 2 AgBrO₃(s)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

2 Ag⁺(aq) + 2 BrO₃⁻(aq) ⇒ 2 AgBrO₃(s)

7 0
3 years ago
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