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meriva
3 years ago
9

The main buffering agents in human blood are h2co3 and hco3. Explain how this buffering system will be able to maintain blood pH

at a steady level when a small amount of a generic acid HA ( with ions H+ and A-) is added
Chemistry
1 answer:
den301095 [7]3 years ago
6 0

Answer:

The base, HCO₃⁻ of the buffering system will neutralize the acid added forming H₂CO₃.

Explanation:

A buffer solution keeps the pH in a narrow range upon the addition of an acid or base. A buffer consists of a pair of a weak acid and its conjugate base, or vice versa, in a pair of a weak base and its conjugate acid. In the case of human blood, the acid is H₂CO₃ and its conjugate base is HCO₃⁻.

The buffering system of the human blood maintain blood pH at a steady level when a small amount of a generic acid HA is added in the following way:

HCO₃⁻ + HA  ⇄  H₂CO₃ + A⁻

The base, HCO₃⁻, will neutralize the acid added forming the H₂CO₃, which is already a component of the buffering system of the human blood. Thus, hydronium ions of the acid added are removed, preventing the pH of blood from becoming acidic.                

On the other hand, when a small amount of a generic base A⁻ is added the following reaction takes place:    

H₂CO₃ + A⁻  ⇄  HCO₃⁻ + HA

In this case, the acid H₂CO₃ will neutralize the base added to form the base HCO₃⁻, which is already a component of the buffering system. Thus, the base added are removed from the blood, preventing the pH of blood from becoming basic.  

Since, the acid or its conjugate base will react with the base or acid added, to neutralizing it and forming the species that conform the buffer solution, the pH is being maintained at a steady level.  

In the process above, the addition of a small amount of an acid or a base won't change in a significant way the concentrations of the two components of the buffering system. This buffering mechanism prevents the blood from becoming acidic or basic.  

                   

I hope it helps you!

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Please help with chemistry question... It would help me tremendously and if you can, please show work :)?
Alexxandr [17]

Answer:

5.06 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mass of S2O = 175g

Volume (V) = 16600 mL

Temperature (T) = 195°C

Pressure (P)

Step 2:

Determination of the number of mole of S2O in 175g of S2O.

Mass of S2O = 175g

Molar Mass of S2O = (32x2) + 16 = 64 + 16 = 80g/mol

Number of mole of S2O =.?

Number of mole = Mass/Molar Mass

Number of mole of S2O = 175/80

Number of mole of S2O = 2.1875 moles

Step 3:

Conversion to appropriate units.

It is essential to always express the various variables in the right units of measurement in order to obtain the desired answer in the right units.

For volume:

1000mL = 1L

Therefore, 16600mL = 16600/1000 = 16.6L

For temperature:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = 195°C

Temperature (Kelvin) = 195°C + 273 = 468K

Step 4:

Determination of the pressure.

The pressure can be obtained by the application of the ideal gas equation. This is illustrated below:

Volume (V) = 16.6L

Temperature (T) = 468K

Number of mole (n) = 2.1875 moles

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =

PV = nRT

P x 16.6 = 2.1875 x 0.082 x 468

Divide both side by 16.6

P = (2.1875 x 0.082 x 468) /16.6

P = 5.06 atm

Therefore, the pressure is 5.06 atm

6 0
3 years ago
Micah is investigating the transformation between potential and kinetic energy within a system. He uses a swinging pendulum in h
slega [8]

Answer: The total energy is maintained as energy transformed

Explanation:

The kinetic energy and potential energy is been maintained as each of the experiment is been performed which is 50Joules

5 0
3 years ago
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What type of energy is stored in the earths crust and produces earthquakes
Svetradugi [14.3K]
A rapid release of stored up energy 
8 0
3 years ago
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During lab, a student used a Mohr pipet to add the following solutions into a 25 mL volumetric flask. They calculated the final
kompoz [17]

Answer:

(FeSCN⁺²) = 0.11 mM

Explanation:

Fe ( NO3)3 (aq) [0.200M] + KSCN (aq) [ 0.002M] ⇒ FeSCN+2

M (Fe(NO₃)₃  = 0.200 M

V (Fe(NO₃)₃ =  10.63 mL

n (Fe(NO₃)₃ = 0.200*10.63 = 2.126 mmol

M (KSCN) =  0.00200 M

V (KSCN) = 1.42 mL

n (KSCN) =  0.00200 * 1.42 = 0.00284 mmol

Total volume = V (Fe(NO₃)₃  + V (KSCN)

                       = 10.63 + 1.42

                       = 12.05 mL

Limiting reactant = KSCN

So,

FeSCN⁺² = 0.00284 mmol

M (FeSCN⁺²) = 0.00284/12.05

                     = 0.000236 M

Excess reactant = (Fe(NO₃)₃

n(Fe(NO₃)₃ =  2.126 mmol -  0.00284 mmol

                  =2.123 mmol

For standard 2:

n (FeSCN⁺²) = 0.000236 * 4.63

                    =0.00109

V(standard 2) = 4.63 + 5.17

                       = 9.8 mL

M (FeSCN⁺²)  = 0.00109/9.8

                      = 0.000111 M = 0.11 mM

Therefore, (FeSCN⁺²) = 0.11 mM

7 0
2 years ago
A 10 gram sample of iron reacts with oxygen to form 18.2 grams of ferric oxide. How many grams of oxygen reacted?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 8.2 \ grams}}

Explanation:

According to the Law of Conservation of Mass, the mass of the products must equal the mass of the reactants.

  • mass products = mass reactants

In this problem, the reaction is:

iron + oxygen = ferric \ oxygen

  • The reactants are iron and oxygen. We know the mass of the iron sample is 10 grams.
  • The product is ferric oxide. The mass of the ferric oxide sample is 18.2 grams.

10 \ g + oxygen=18.2 \ g

We want to find how many grams of oxygen reacted. We have to get the oxygen by itself. 10 is being added to oxygen. The inverse of addition is subtraction. Subtract 10 from both sides of the equation.

10 \ g - 10 \ g+ oxygen = 18.2 \ g - 10 \ g

oxygen= 18.2 \ g - 10 \ g

oxygen= 8.2 \ g \\

<u>8.2 grams of oxygen </u>reacted with 10 grams of iron to form 18.2 grams of ferric oxide.

8 0
2 years ago
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