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Naddik [55]
3 years ago
14

Which block do you think will slide down the ramp most quickly?

Chemistry
2 answers:
Oksi-84 [34.3K]3 years ago
8 0
Steel block because if you think about the friction it would make it more fast and therefore it would go faster
tangare [24]3 years ago
5 0
Steel because of friction. When rubber moves over smooth surfaces, it's the molecular forces between the two that are the main cause of friction. But when the surface is rough, it's the deformation of entire molecular layers of rubber that's the chief cause of friction.
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Which bent shape has more repulsion and a smaller bond angle?<br> bent 6A<br> bent 5A
Step2247 [10]
Bent 6A is the answer
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3 years ago
Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below.
zavuch27 [327]

15.63 mol. You need 15.63 mol HgO to produce 250.0 g O_2.

<em>Step 1</em>. Convert <em>grams of O_2 to moles of O_2</em>

Moles of O_2 = 250.0 g O_2 × (1 mol O_2/32.00 g O_2) = 7.8125 mol O_2

<em>Step 2</em>. Use the molar ratio of HgO:O_2 to convert <em>moles of O_2 to moles of HgO </em>

Moles of HgO = 0.8885 mol O_2 × (2 mol HgO/1 mol O_2) = <em>15.63 mol HgO</em>

7 0
3 years ago
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erica [24]

Answer:

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Explanation:

3 0
3 years ago
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Energy produced by nuclear fusion and fission
White raven [17]

Both fission and fusion are nuclear reactions that produce energy, but the applications are not the same. Fission is the splitting of a heavy, unstable nucleus into two lighter nuclei, and fusion is the process where two light nuclei combine together releasing vast amounts of energy.

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3 years ago
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n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
Lorico [155]

Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

pCl₂ = 3.5 × 10⁻⁴ × 0.17 / 0.22

pCl₂ = 2.7 × 10⁻⁴ bar

7 0
3 years ago
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