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3 years ago

MIDDLE SCHOOL SCIENCE- Please help, I will give brainliest to best answer.

Physics

1 answer:

tatyana61 [14]3 years ago

5 0

Answer:

1.) Waves carry energy through empty space or through a medium without transporting matter. While all waves can transmit energy through a medium, certain waves can also transmit energy through empty space. ... When waves travel through a medium, the particles of the medium are not carried along with the wave.

2.) Mechanical Waves are waves which propagate through a material medium (solid, liquid, or gas) at a wave speed which depends on the elastic and inertial properties of that medium. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves. Longitudinal waves vibrating in the direction of propagation while Transverse waves vibrate at right angles to the direction of its propagation.

3.) They can carry a little energy or a lot of energy. They can be transverse or longitudinal. However, all waves have common properties—amplitude, wavelength, frequency, and speed. Amplitude describes how far the medium in a wave moves.

I hope this helps!

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THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THAN

Karo-lina-s [1.5K]

Answer:

450km because this night founder

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3 years ago

Read 2 more answers

A small planet having a radius of 1000 km exerts a gravitational force of 100 N on an object that is 500 km above its surface. I

Mars2501 [29]

<h2>Option C is the correct answer.</h2>

Explanation:

Gravitational force is given by

$F=\frac{GMm}{r^2}$

G=6.674×10⁻¹¹ m³⋅kg⁻¹⋅s⁻²

M = Mass of object 1

m = mass of object 2

r = Distance between objects.

Here only variable is r value.

In case 1

$100=\frac{GMm}{(1000+500)^2}\\\\GMm=100\times 1500^2$

In case 2

$F=\frac{GMm}{(1000+500+500)^2}\\\\F=\frac{GMm}{2000^2}\\\\F=\frac{100\times 1500^2}{2000^2}\\\\F=56.25N$

Option C is the correct answer.

7 0

4 years ago

A crate of mass 190 kg sits on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.4, an

Oxana [17]

Answer:

Explanation:

Mass of 190kg

Coefficient of static friction is 0.4

Coefficient of kinetic friction 0.36

Horizontal force= 500N

Taking g=9.81m/s^2.

The weight of the body my

W=190×9.81=1863.91N

There is a normal acting on the body which is equal to the weight

N=W=1863.91N

Frictional force(fr) is acting on the body and it is opposite the horizontal force.

The minimum force to be overcome before the object can start to move is Fr = μsN

Fr= μsN. μs=0.4

Fr= 0.4×1863.91

Fr=745.56N.

Since the horizontal force (500N) is not up to the minimum force to make the object move, then the force of 500N the body is still at rest.

Then the frictional force at that time is equal to the horizontal force

Therefore

Functional force = 500N

b. Mass of asteroid is

M=2000kg

Asteroid velocity at a particular instant is,

U=(-1.30x10^4, 4.20x10^4, 0)m/s

Magnitude of U is

U=√(-1.30×10^4)^2 +(4.2×10^4)^2+0

U=√1.933E9

U=4.39×10^4m/s

Position of the asteroid from the centre of the earth is,

R= (6.00x10^6, 10.00x10^6, 0)m.

The magnitude of the radius is

R = √(6.00x10^6)^2+ (10.00x10^6)^2+ 0^2

R=√3.6E13+10E13+0

R=√13.6E13

R=1.17E7m

R^2=13.6E13m

The mass of the earth is

Me=5.97x10^24 kg

The momentum of the asteroid after time, t=1.5×10^3s

Given that G=6.67x10^-11Nm^2/kg^2

Momentum is

Mv-Mu=Ft

There the new momentum will be

Mv=Ft+Mu

Now we the to find the force the earth exert on the asteroid by using

F=GMMe/R^2

F=6.67E-11 ×2000× 5.97E24 /13.6E13

F=7.964E17/13.6E13

F=5855.88N

The new momentum

Mv= Mu+Ft

Mv= 2000(4.39E4)+5855.88(1.5E3)

Mv=9.66E7kgm/s

The new momentum is 9.66×10^7 Kgm/s

8 0

3 years ago

What is the net force that accelerates an object on an inclined plane due to the effect of gravity, normal force and friction of

Olenka [21]

Answer:

Explanation:

Check the attachment for solution

8 0

4 years ago

The coefficient of kinetic friction between Gary's shoes and the wet kitchen floor is 0.09. If Gary has a mass of 65 kg, what is

mariarad [96]

Answer:

57 N

Explanation:

Draw a free body diagram. There are three forces:

Weight force mg pulling down.

Normal force N pushing up.

Friction force F pushing horizontally.

Sum of the forces in the y direction:

∑F = ma

N − mg = 0

N = mg

Friction force is the product of normal force and coefficient of friction:

F = Nμ

F = mgμ

F = (65 kg) (9.8 m/s²) (0.09)

F = 57.3 N

Rounded, the friction force is 57 N.

8 0

3 years ago