How many moles of ammonia (nh3 will be produced from 4.0 moles of nitrogen (n2?

1 answer:

3 0

Standard equation would be N2(g)+3H2(g)==>2NH3(g), so through stoichiometry, (4 mol N2)(2mol NH3/1 mol N2), assuming excess H2, would yield 8 moles of NH3.

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LOOK AT THE IMAGE FOR THE QUESTION PLEASE

Nostrana [21]

From the atomic clock that utilizes C-133 which has an approximate frequency of 9.193 x 109 Hz. The wavelength of the energy is calculated to be 0.0326m.

From the given information:

The frequency f = 9.193 × 10⁹ Hz = 9.193 × 10⁹ 1/s
The wave speed c = 3.00 × 10⁸ m/s

Recall that:

The wavelength is the spatial successive distance between two crests of a wave and can be expressed by the formula:

$\mathbf{\lambda = \dfrac{c}{f}}$

$\mathbf{\lambda = \dfrac{3.00 \times 10^8 \ m/s }{9.193 \times 10^9 \ 1/s}}$

$\mathbf{\lambda =0.0326 \ m}$

Therefore, we can conclude that the wavelength of the atomic clock is 0.0326m. As such Option D is correct.

Learn more about wavelength here:

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DedPeter [7]

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Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be.

dmitriy555 [2]

Answer: The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Explanation:

There are 4 quantum numbers:

Principal Quantum number (n) specifies the energy of the electron in a shell.
Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of $+\frac{1}{2}$ or $-\frac{1}{2}$