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zmey [24]
2 years ago
6

Can anyone fill in the answers?

Chemistry
1 answer:
Arte-miy333 [17]2 years ago
6 0
Hi, P.S. The atomic number will always be the same as the number of protons...

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if anyone has chemistry on edge and has the analyzing chemical reactions project can i please have your insta? i really need it.
Sedbober [7]

Explanation:

id -9384026088

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7 0
3 years ago
In an experiment, the same mass of magnesium metal reacted with the same amount of two different acids. the acid used in reactio
denpristay [2]

The mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

<h3>What is the mole ratio of a reaction?</h3>

The mole ratio of a reaction is the ratio in which the reactants and products of a given reaction occur for the reaction to proceed to completion.

The mole ratio of a reaction is also known as the stoichiometry of the reaction.

The equation of the two reactions are given below:

Mg + 2HCl \rightarrow MgCl_2 + H_2

Mg + 2CH_3COOH \rightarrow (CH_3COO)_2Mg + H_2 \\

From the equation of the reaction reaction, an equal volume of hydrogen gas will be produced by the two reactions.

Therefore, the mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

Learn more about mole ratio at: brainly.com/question/19099163

#SPJ1

6 0
1 year ago
PLEASE HELP!!!!!!!
Basile [38]

Answer:

2nd option

Explanation:

5 0
3 years ago
Write a nuclear equation for the beta decay of Promethium-165
padilas [110]

Answer:

see your answer in pic

Explanation:

4 0
2 years ago
A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°C. What is the magnitude of k at 95.0°C if Ea =
never [62]

Answer:

k ≈ 9,56x10³ s⁻¹

Explanation:

It is possible to solve this question using Arrhenius formula:

ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )

Where:

k1: 1,35x10² s⁻¹

T1: 25,0°C + 273,15 = 298,15K

Ea = 55,5 kJ/mol

R = 8,314472x10⁻³ kJ/molK

k2 : ???

T2: 95,0°C+ 273,15K = 368,15K

Solving:

ln\frac{k2}{k1} = 4,257

\frac{k2}{k1} = 70,593

{k2} = 9,53x10^3 s^{-1}

<em>k ≈ 9,56x10³ s⁻¹</em>

I hope it helps!

5 0
2 years ago
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