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cluponka [151]
3 years ago
7

Among the following, which element has the lowest ionization energy?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
4 0
The answer is A. Na

because it's<span /> 5,1391
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Choose the FALSE statement.
Mariana [72]

Answer:

C. The half-life of C-14 is about 40,000 years.

Explanation:

The only false statement from the options is that the half-life of C-14 is 40,000yrs.

The half-life of an isotope is the time it takes for half of a radioactive material to decay to half of its original amount. C-14 has an half-life of 5730yrs. This implies that during every 5730yrs, C-14 will reduce to half of its initial amount.

  • All living organisms contain both stable C-12 and the unstable isotope of C-14
  • The lower the C-14 compared to the C-12 ratio in an organism, the older it is.
5 0
3 years ago
2c2h6 + 7o2 = 4co2 + 6h2o <br> what mass of co2 will be produced from the reaction of 37.5 g c2h6
ivanzaharov [21]

Answer:

use n=m/M (moles=mass/molar mass) to find out how many moles of C2H6 there are in 60g

Explanation:

8 0
3 years ago
Write both answers to at least two decimal places. Calculate the pH of a 0.160 M solution of KOH.Part 2 (1 point) Calculate the
Evgen [1.6K]

To calculate the pH of a solution, we first need to find the concentration of hydronium ions in the solution. Since KOH is a strong base, it dissociates completely in water to produce hydroxide ions (OH-) and potassium ions (K+).

The concentration of hydronium ions in a solution of KOH can be calculated using the concentration of hydroxide ions and the equilibrium constant for water, which is equal to 1.00 x 10^-14 at 25 degrees Celsius.

The concentration of hydroxide ions in a 0.160 M solution of KOH is equal to the concentration of KOH, which is 0.160 M. The concentration of hydronium ions in the solution can be calculated using the equation below:

[H3O+] = (1.00 x 10^-14) / [OH-]

Substituting the concentration of hydroxide ions into the equation above, we get:

[H3O+] = (1.00 x 10^-14) / (0.160 M) = 6.25 x 10^-13 M

To calculate the pH of the solution, we need to take the negative logarithm of the concentration of hydronium ions. This can be done using the equation below:

pH = -log([H3O+])

Substituting the concentration of hydronium ions into the equation above, we get:

pH = -log(6.25 x 10^-13) = 12.20

The pH of a 0.160 M solution of KOH is 12.20.

To calculate the pOH of a solution, we first need to find the concentration of hydroxide ions in the solution. Since we already calculated this value above, we can simply use the concentration of hydroxide ions we found earlier: 0.160 M.

To calculate the pOH of the solution, we need to take the negative logarithm of the concentration of hydroxide ions. This can be done using the equation below:

pOH = -log([OH-])

Substituting the concentration of hydroxide ions into the equation above, we get:

pOH = -log(0.160 M) = 1.80

The pOH of a 0.160 M solution of KOH is 1.80.

Learn more about pH:
brainly.com/question/28864035

#SPJ4

7 0
9 months ago
How many significant figures are in 0.000128?
san4es73 [151]
Three sig figs, the leading zeros are not sig figs
6 0
3 years ago
_ Have both metallic and nonmetallic properties.
Ahat [919]
The answer is Metalloids!
6 0
2 years ago
Read 2 more answers
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