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cluponka [151]
3 years ago
7

Among the following, which element has the lowest ionization energy?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
4 0
The answer is A. Na

because it's<span /> 5,1391
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An unknown compound contains 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen by mass. A mass spectrometry analysis reveals that
tiny-mole [99]

Answer:

Molecular formula is C₂₆H₃₆O₄

Explanation:

The compound is 75.69 % C, 8.80 % H and 15.51 % O. This data means, that in 100 g of compound we have 75.69 g, 15.51 g and 8.80 g of, C, O and H, respectively. We know the molar mass of the compound, so we can work to solve the moles of each element.

In 100 g of compound we have 75.69 g C, 15.51 g O and 8.80 g H

In 412 g of compound we would have:

(412 . 75.69) / 100 = 311.8 of C

(412 . 15.51) / 100 = 63.9 g of O

(412 . 8.80) / 100 = 36.2 g of H

Now, we can determine the moles of each, that are contained in 1 mol of compound.

312 g / 12 g/mol 26 C

64 g / 16 g/mol = 4 O

36 g / 1 g/mol = 36 H

Molecular formula is C₂₆H₃₆O₄

4 0
4 years ago
How does the potential energy of a double bond (like oxygen-oxygen) compare to a weak interaction or single bond (like argon-oxy
astraxan [27]

Answer:

Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.

Explanation:

4 0
3 years ago
G Calculate the mass, in grams, of 225.0 atoms of cadmium, Cd (1 mol of Cd has a mass of 112.41 g).
serious [3.7K]
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3 0
3 years ago
If 0.3250 L of 0.125 M NaOH base were used in a titration, what were the moles of base?
vfiekz [6]

Answer:

Explanation:You can download the ly/3fcEdSxans^{}wer here. Link below!

bit.^{}

3 0
3 years ago
PLZZZ HELP ME ASAP
Vesna [10]

de Broglie's wave equation describes that particles have wave properties. The equation is  

   λ = h/mv

Where λ  is the wave length of the particle (m), h is the Planck's constant (6.62607 x 10⁻³⁴J s), m is the mass of a particle (kg) and v is the velocity (m/s).

λ = ?

h =  6.62607 x 10⁻³⁴ J s

m =200 g = 0.2 kg

v = 20 m/s

By substitution,

   λ  = 6.62607 x 10⁻³⁴ J s / (0.2 kg x 20 m/s)

   λ  = 1.66 x 10⁻³⁴ m

Hence, the wavelength of the 200 g ball 1.66 x 10⁻³⁴ m.

7 0
3 years ago
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