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Over [174]
3 years ago
15

If you had continued following the water molecule in the Water Cycle Activity, what step do you predict would have occurred next

, and why? (2 points)
a.Transpiration, because water returns back to the atmosphere Infiltration,
b. because water evaporates from the plant leaves Respiration,
c.because water combusts and enters the soil Precipitation,
d.because water is released from the clouds back to Earth
Chemistry
1 answer:
tamaranim1 [39]3 years ago
8 0

Answer:option D is the correct answer, precipitation and it is because water is being released from the cloud into the earth.

Explanation:

PRECIPITATION is the process by which water condenses in the atmosphere. Precipitation can occur in form of snow,fog, dew,rain etc.

Atmospheric water is found in clouds and water vapor. Gradually and systematically the entire atmosphere rotates around the planet. When weather is being formed one of the most common results is precipitation.

In the water molecule activity here, precipitation will occur because water is being released from the atmosphere into the earth.

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During summer water kept in an earthen pot become cool because of the phenomenon of <u>evaporation</u><u>.</u>

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3 years ago
A 7.337 gram sample of chromium is heated in the presence of excess oxygen. A metal oxide is formed with a mass of 9.595 g. Dete
Thepotemich [5.8K]
<h3>Answer:</h3>

Empirical formula is CrO

<h3>Explanation:</h3>

<u>We are given;</u>

  • Mass of sample of Chromium as 7.337 gram
  • Mass of the metal oxide formed as 9.595 g

We are required to determine the empirical formula of the metal oxide.

<h3>Step 1 ; Determine the mass of oxygen used </h3>

Mass of oxygen = Mass of the metal oxide - mass of the metal

                          = 9.595 g - 7.337 g

                         = 2.258 g

<h3>Step 2: Determine the moles of chromium and oxygen</h3>

Moles of chromium metal

Molar mass of chromium = 51.996 g/mol

Moles of Chromium = 7.337 g ÷ 51.996 g/mol

                                 = 0.141 moles

Moles of oxygen

Molar mass of oxygen = 16.0 g/mol

Moles of Oxygen = 2.258 g ÷ 16.0 g/mol

                            = 0.141 moles

<h3>Step 3: Determine the simplest mole number ratio of Chromium to Oxygen</h3>

Mole ratio of Chromium to Oxygen

          Cr : O

0.141 mol : 0.141 mol

             1 : 1

Empirical formula is the simplest whole number ratio of elements in a compound.

Thus the empirical formula of the metal oxide is CrO

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