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2 years ago

5

you are standing on top of a 344 m tall building. A drone operated by your friend is headed straight down, at a speed of 37.0 m/

s. Just as the drone passes you, you release a tennis ball off the roof. How fast is the ball going when it passes the drone?

1 answer:

Kazeer [188]2 years ago

5 0

Answer:

v = 74.0m/s

Explanation:

Look at the photo.

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A man has a mass of 110kg. What is his weight?

Stells [14]

His weight depends on where he is, because

Weight = (mass) x (gravity in the place where the mass is) .

For example:

-- If this man is on Mars, his weight is (110 kg) x (3.7 m/s²) = 408 Newtons

-- If he is on the Moon, his weight is (110 kg) x (1.6 m/s²) = 176 Newtons

-- If he is on Earth, his weight is (110 kg) x (9.8 m/s²) = 1,078 Newtons

-- If he is in a spacecraft coasting from one to another, his weight is zero.

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2 years ago

A softball with a mass of 0.11 kg goes moves at a speed of 12 m/s, then the ball is hit by a bat and rebounds in the opposite di

dimulka [17.4K]

=1244 and that's from my math book

7 0

2 years ago

The loop is in a magnetic field 0.20 T whose direction is perpendicular to the plane of the loop. At t = 0, the loop has area A

love history [14]

Answer:

Part a)

$EMF = 14 \times 10^{-3} V$

Part b)

$EMF = 15.67 \times 10^{-3} V$

Explanation:

As we know that magnetic flux through the loop is given as

$\phi = B.A$

now we have

$\phi = B\pi r^2$

now rate of change in flux is given as

$\frac{d\phi}{dt} = B(2\pi r)\frac{dr}{dt}$

now we know that

$A = \pi r^2$

$0.285 = \pi r^2$

$r = 0.30 m$

Now plug in all data

$EMF = (0.20)\times 2\pi\times (0.30) \times (0.037)$

$EMF = 14 \times 10^{-3} V$

Part b)

Now the radius of the loop after t = 1 s

$r_1 = r_0 + \frac{dr}{dt}$

$r_1 = 0.30 + 0.037$

$r_1 = 0.337 m$

Now plug in data in above equation

$EMF = (0.20)\times 2\pi\times (0.337) \times (0.037)$

$EMF = 15.67 \times 10^{-3} V$

5 0

3 years ago

Please helppppppp!!!!!!!!!!!!!!!!!!!!!!!!

kykrilka [37]

Answer:

I think the Bulb No. 2 will stop emitting light if the bulb No. 1 burns out.

3 0

2 years ago

Ask Your Teacher A basketball player shoots toward a basket 5.8 m away and 3.0 m above the floor. If the ball is released 1.7 m

const2013 [10]

Answer:

The answer to your question is vo = 5.43 m/s

Explanation:

Data

distance = d= 5.8 m

height = 3 m

height 2 = 1.7 m

angle = 60°

vo = ?

g = 9.81 m/s²

Formula

hmax = vo²sinФ/ 2g

Solve for vo²

vo² = 2ghmax / sinФ

Substitution

vo² = 2(9.81)(3 - 1.7) / 0.866

Simplification

vo² = 19.62(1.3) / 0.866

vo² = 25.51 / 0.866

vo² = 29.45

Result

vo = 5.43 m/s

5 0

3 years ago