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motikmotik
4 years ago
13

What is the oxidation number of cl− in the perchlorate ion

Chemistry
1 answer:
Yuri [45]4 years ago
5 0

Answer:

The answer is: +7

Explanation:

Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.

Perchlorate ion is a molecule with a chemical formula: ClO₄⁻

The oxidation state of oxygen in ClO₄⁻ = -2,

the total charge on the ClO₄⁻ molecule = -1,

let the oxidation state of chlorine be x

<u><em>As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.</em></u>

⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule

⇒ x + (-2) × 4 = -1

⇒ x + (-8) = -1

⇒ x = -1 + 8 = +7

⇒<u> </u><u>x = +7</u>

<u>Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7</u>

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The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, (Br_2) = 159.8 g/mol

Putting values in above equation, we get:

\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol

Hence, the amount of liquid bromine produced is 4.79 moles.

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3 years ago
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4 years ago
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