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Paraphin [41]
3 years ago
12

What is the momentum of a man of mass 10kg when he walks with a uniform velocity of 2m/s.

Physics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer:

Momentum(p) = 20kgm/s

Explanation:

Given

Mass = 10kg

Velocity = 2m/s

Required

Calculate the momentum of the man

Momentum is calculated as thus

Momentum(p) = Mass(m) * Velocity(v)

or

p = mv

So; to solve this question; we simply substitute 10kg for mass and 2m/s for velocity in the above formula;

The formula becomes

Momentum(p) = 10kg * 2m/s

Momentum(p) = 10 * 2 * kg * m/s

Momentum(p) = 20kgm/s

Hence, the momentum of the man is 20kgm/s

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g is incident on 3 successive sheets of polarizing material. The transmission axis of the first sheet is vertical. The transmiss
murzikaleks [220]

Answer:

The intensity of light passing from the third polarizer is 3Io/16.

Explanation:

The law of Malus is given by

I=I_o cos^2\theta

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

I' = \frac{I_o}{2}

The intensity of light passing from the second polarizer is

I''=\frac{I_o}{2}\times cos^230 =\frac{3I_o}{8}

The intensity of light passing from the third polarizer is

I''' = \frac{3I_o}{8}\times cos^2 60\\\\\\I''' = \frac{3I_o}{16}

6 0
3 years ago
Calculate the index of refraction for a medium in which the speed of light is 2.1x 108 m/s. The speed of light in vacuum is 3x10
strojnjashka [21]

Answer:

n = 1.42

Explanation:

The refractive index for a medium is given by the ratio of the speed of light in vacuum to the speed of light in a medium.

n=\dfrac{c}{v}\\\\n=\dfrac{3\times 10^8}{2.1\times 10^8}\\\\n = 1.42

So, the refractive index of the medium is 1.42.

5 0
3 years ago
Energy from the Sun arrives at the top of the Earth’s atmosphere with an intensity of 1.30kW/m21.30⁢kW/m2. How long does it take
vivado [14]

Answer:

T=1.384×10⁶seconds

Explanation:

Given data

p (Intensity)=1.30 kw/m²

E (Energy)=1.8×10⁹ J

A (Area)=1.00 m²

T (Time required)=?

Solution

E=PT   ................eq(i)

where E is energy

P is radiation power

T is time

Radiating Power is given as

P=pA

Where p is intensity

A is Area

Put P=pA in eq(i) we get

E=pAT

T=E/pA

T=\frac{(1.8*10^{9}}{(1.30*10^{3} )*(1.00)}  )\\T=1.38*10^{6} seconds

3 0
3 years ago
Do we include signs if we calculate Electric field strength?
expeople1 [14]
Yes because if not people wouldn't understand how did you calculate electric field strength.
6 0
3 years ago
Which factor below does NOT affect how fast a solute dissolves in a solvent?
vodomira [7]
There is no factor on your list of choices that has any effect.
7 0
3 years ago
Read 2 more answers
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