What is the momentum of a man of mass 10kg when he walks with a uniform velocity of 2m/s.
1 answer:
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The table is:
t(s) vx(m/s)
0 0
10 23
20 46
30 69
a) from the data in the table, we observe that the acceleration is constant (because the rate of change in velocity is the same for each time interval of 10 seconds), so we can choose just one interval and calculate the acceleration as the ratio between the change in velocity and the change in time. Taking the first interval, we find
b) To find the jet's acceleration in g's, we just need to divide the acceleration in m/s^2 by the value of g, the acceleration of gravity (9.81 m/s^2), so we find
c) the wheels leave the ground when the jet reaches its take-off velocity, which is 82 m/s.
At t=0s, the velocity of the jet is 0. We know that the acceleration is constant (a=2.3 m/s^2), so we can find the time t at which the jet reaches a velocity vf=82 m/s by using the equation
Re-arranging and substituting numbers, we find