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Blizzard [7]
3 years ago
13

The speed of light in a vacuum is approximately 2.99 × 108 m/s, and the speed of light through a piece of glass is approximately

1.97 × 108 m/s.
What is the index of refraction for the piece of glass?

a) 0.66
b) 1.52
c) 1.02 × 10^8
d) 4.96 × 10^8
Physics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

The index of refraction for the piece of glass is 1.52

Explanation:

Given that,

Speed of light in vacuum, c=2.99\times 10^8\ m/s

Speed of light through a piece of glass is, v=1.97\times 10^8\ m/s

The ratio of speed of light in vacuum to the speed of light in a medium is called refractive index i.e.

n=\dfrac{c}{v}

n=\dfrac{2.99\times 10^8}{1.97\times 10^8}

n = 1.52

Hence, the index of refraction for the piece of glass is 1.52

exis [7]3 years ago
6 0

Option (b) is correct.The index of refraction for the glass is 1.52

Explanation:

velocity of light in vacuum= C= 2.99 x 10⁸m/s

Velocity of light in glass = V= 1.97 x 10⁸m/s

The refractive index is given by n=\frac{c}{v}

n= 2.99 x 10⁸/1.97 x 10⁸m/s

n= 1.52

Thus the refractive index of glass is 1.52

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Rama09 [41]

Answer:

(a) 0.613 m

(b) 0.385 m

(c) vₓ = 1.10 m/s, vᵧ = 3.50 m/s

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Explanation:

(a)  Take down to be positive.

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 0.350 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (0.350 s) + ½ (10 m/s²) (0.350 s)²

Δy = 0.613 m

(b) Given in the x direction:

v₀ = 1.10 m/s

a = 0 m/s²

t = 0.350 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (1.10 m/s) (0.350 s) + ½ (0 m/s²) (0.350 s)²

Δx = 0.385 m

(c) Find: vₓ and vᵧ

vₓ = aₓt + v₀ₓ

vₓ = (0 m/s²) (0.350 s) + 1.10 m/s

vₓ = 1.10 m/s

vᵧ = aᵧt + v₀ᵧ

vᵧ = (10 m/s²) (0.350 s) + 0 m/s

vᵧ = 3.50 m/s

The magnitude is:

v² = vₓ² + vᵧ²

v = 3.68 m/s²

The direction is:

θ = atan(vᵧ / vₓ)

θ = 72.6° below the horizontal

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Answer:

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