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Blizzard [7]
3 years ago
13

The speed of light in a vacuum is approximately 2.99 × 108 m/s, and the speed of light through a piece of glass is approximately

1.97 × 108 m/s.
What is the index of refraction for the piece of glass?

a) 0.66
b) 1.52
c) 1.02 × 10^8
d) 4.96 × 10^8
Physics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

The index of refraction for the piece of glass is 1.52

Explanation:

Given that,

Speed of light in vacuum, c=2.99\times 10^8\ m/s

Speed of light through a piece of glass is, v=1.97\times 10^8\ m/s

The ratio of speed of light in vacuum to the speed of light in a medium is called refractive index i.e.

n=\dfrac{c}{v}

n=\dfrac{2.99\times 10^8}{1.97\times 10^8}

n = 1.52

Hence, the index of refraction for the piece of glass is 1.52

exis [7]3 years ago
6 0

Option (b) is correct.The index of refraction for the glass is 1.52

Explanation:

velocity of light in vacuum= C= 2.99 x 10⁸m/s

Velocity of light in glass = V= 1.97 x 10⁸m/s

The refractive index is given by n=\frac{c}{v}

n= 2.99 x 10⁸/1.97 x 10⁸m/s

n= 1.52

Thus the refractive index of glass is 1.52

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algol13

Answer:

gamma rays  < X-ray  < ultraviolet ray < visible light < infrared  < radio wave

Explanation:

given light form,

A) radio waves,B) infrared,C) visible light,D) ultraviolet,E) X-rays,F) gamma rays

we know,

wavelength of radio wave = 10000 Km

wavelength of infrared = 700 nanometers (nm) to 1 millimeter (mm)

wavelength of visible light = 380 to 740 nm

wavelength of ultraviolet ray = 10 nm to 400 nm

wavelength of X-ray =  0.01 to 10 nm

wavelength of gamma rays = 100 picometer

so, the order of rays.

gamma rays  < X-ray  < ultraviolet ray < visible light < infrared  < radio wave

6 0
3 years ago
Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an
SpyIntel [72]

Answer:

a) 2.43 m/s

b) 4.83 m/s

c) 0.023 m/s²

Explanation:

a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration

Speed = Distance / Time

\text{Speed}=\frac{510}{210}=2.43\ m/s

Velocity of car A is 2.43 m/s

t = Time taken = 210 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 510 m

a = Acceleration

c)

s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2

Acceleration of car B is 0.023 m/s²

b)

v=u+at\\\Rightarrow v=0+0.023\times 210\\\Rightarrow v=4.83\ m/s

Final velocity of car B is 4.83 m/s

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Explanation:

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You have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3
jeka57 [31]

Answer:

W = 0J

Explanation:

The work done by the dresser is described as

W = f d (cos θ)

F has been given as the weight of this dresser. And it is 3500 N

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When you put these values into the equation

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