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Snowcat [4.5K]
4 years ago
11

Which substance(s) will be good conductors of electricity?

Physics
2 answers:
Igoryamba4 years ago
8 0

Answer:

copper like just look at battery today they hold it now

Paul [167]4 years ago
6 0

Answer:Metallic Conductors

Explanation:It is because it is so closely packed so that it the resistor's resistance are very low.

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Naily [24]

Answer:

The answer is A good luck :P

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3 years ago
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A street lamp weighs 150N. It is supported by two wires that form an angle of 120° with each other. The tensions in each wire ar
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60

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4 0
3 years ago
JOSEPH JOGS FROM END A TO OTHER END B OF A straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back
zzz [600]
(a) The average speed from A to B would be 1.76 metre per second and the average velocity from A to B would also be 1.76 metre per second 

<span>(b) The average speed from A to C would be 1.73 metre per second and the average velocity from A to C would be 0.87 metre per second</span>
3 0
3 years ago
How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?
inysia [295]

1 coulomb of electric charge is carried by  6.25 x 10^18 electrons

1 Ampere = 1 coulomb per second
10 A = 10 coulombs per second

(2.0 x 10^20 electrons) x (coul / 6.25 x 10^18 electrons) / (10 coul/sec) =

         (2.0 x 10^20) / (6.25 x 10^18 x 10)    sec  =  <em>3.2 seconds</em>


6 0
3 years ago
The graph above shows the position and time calculate the velocity of the particle from T=0s to T=4s?
zzz [600]

Answer:

The velocity of the particle from T = 0 s to T = 4 s is;

0.5 m/s

Explanation:

The given parameters from the graph are;

The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m

The displacement covered at time, t₂ = 4 s is x₂ = 3 m

The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;

The \ slope \ of \ the \ displacement \ time \ graph, \ m =velocity, \ v= \dfrac{x_2 - x_1}{t_2 - t_1}

Therefore, \ the \ velocity \ of \ the \ particle \ v  = \dfrac{3 \  m - 1 \ m}{4 \ s - 0 \ s}  = \dfrac{2 \ m}{4 \  s} = \dfrac{1}{2} \ m/s

The velocity of the particle from t = 0 s to t  = 4 s = 1/2 m/s = 0.5 m/s.

3 0
3 years ago
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