Question

A car is making a 60 mi trip. It travels the first half of the total distance 30.0 mi at 8.00 mph and the last half of the total distance 30.0 mi at 36.00 mph. (a) What is the total time in hours of the trip? Keep two decimal places.

Answer 1

Answer:

t = 4.58 hours

Explanation:

car trip = 60 miles

first half trip of  30 mile at 8 mph.

second half of 30 mile at 36 mph.

distance = speed × time                  

$time = \dfrac{distance}{speed}$

for first half time taken                      

$t_1 = \dfrac{30}{8}$

$t_1 = 3.75\ hours$

for second half distance time taken

$t_2 = \dfrac{30}{36}$

$t_2 = 0.833\ hours$

total time taken

t = t₁  + t₂                                            

t = 3.75 + 0.833

t = 4.58 hours

Answer 2

Answer:

total time =4.583 hour

Explanation:

We have given total distance = 60 mi

It is given that half of the distance traveled by a speed of 8 mph

We know that $time\ t=\frac{distance }{speed}=\frac{30}{8}=3.75hour$

And second half of the distance traveled by a speed of 36 mph

So time $t=\frac{distance }{speed}=\frac{30}{36}=0.833hour$

So total time = 3.75 + 0.833 =4.583 hour