Answer:
2.6166 moles
Explanation:
stp means: T=273k p=101.3kpa
R= 8.31(constant) v=58.6
using the ideal gas law; pv=nRt
101.3 x 58.6 = n x 8.31 x 273
n= (101.3 x 58.6)\(8.31 x 273)
n= 2.6166moles
Answer:

Explanation:
Hello there!
In this case, since this imaginary gas can be modelled as an ideal gas, we can write:

Which can be written in terms of density and molar mass as shown below:

Thus, by computing the pressure in atmospheres, the resulting density would be:

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Answer:
t = 50 s
Explanation:
P = W/t
Solving for t,
t = W/P = (3430000 J)/(68600 Watts)
= 50 s
Note: 1 Watt = 1 J/s
Mg(c) + 237shi (4z) ¥at h2)
Question is incomplete, complete question is;
A 34.8 mL solution of
(aq) of an unknown concentration was titrated with 0.15 M of NaOH(aq).

If it takes 20.4 mL of NaOH(aq) to reach the equivalence point of the titration, what is the molarity of
? For your answer, only type in the numerical value with two significant figures. Do NOT include the unit.
Answer:
0.044 M is the molarity of
(aq).
Explanation:
The reaction taking place here is in between acid and base which means that it is a neutralization reaction .
To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

0.044 M is the molarity of
(aq).