At t=0, the particle was at its equilibrium position. The time period is 32 seconds, so in 8 seconds, it will reach the extreme location once, and hence, in 8 seconds, it will cover a distance equivalent to its amplitude.
I think it may be c, 1.7 v. I work with electricity a lot.
when a car moves on a rode and it,s force is =100,000N
Matter is made up of molecules and atoms
The force between the two particles will quadruple
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
d is the separation between the two charges
In this problem, let's call F the initial force between the two charges, when they are at a distance of d.
Later, the distance between the two particles is halved, so the new distance is:

This means that the new electrostatic force will be:

Therefore, the force between the two particles will quadruple.
Learn more about electrostatic force:
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