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3 years ago

The force of repulsion between two like-charged particles will increase if

Physics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

the distance between the charged particles is decreased.

svlad2 [7]3 years ago

5 0

If they're brought closer together

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Help me ultra sound vs infrasound

hodyreva [135]

Answer:

ultrasound: high pitch, above the human range of hearing, reflects back

infrasound: longitudinal waves, in the human range, low pitch

Explanation:

4 0

3 years ago

The units we use to measure the sound intensity level are _____.

Sergio039 [100]

Answer:

decibels (dB)

Explanation:

The sound intensity level is a quantity derived from the sound intensity.

The intensity of a wave is defined as the power of the source of the wave divided by the area through which the power of the wave is spread, mathematically:

$I=\frac{P}{A}$

where

P is the power of the source

$A=4\pi r^2$ is the surface area over which the wave spreads (assuming that the wave propagates in all directions, it corresponds to the surface area of a sphere of radius $r$ , where r is the distance between the source of the wave and the observer)

For sound waves, the intensity is often expressed using another unit, called decibel (dB), defined as follows:

$\beta(dB)=10Log_{10}(\frac{I}{I_0})$

where

$\beta$ is the sound intensity level in decibels

I is the intensity of the sound wave

$I_0=1\cdot 10^{-12} W/m^2$ is the threshold intensity of a sound that a person can normally hear.

3 0

3 years ago

Two parallel wires separated by a distance of 0.6 m each carry current in the same direction. One wire is carrying a current of

mart [117]

Answer:

The value is $B = 3.33 *10^{-6} \ T$

Explanation:

From the question we are told that

The distance of separation is $d = 0.6 \ m$

The current on the one wire is $I_1 = 9 \ A$

The current on the second wire is $I_2 = 4 \ A$

Generally the magnitude of the field exerted between the current carrying wire is

$B = B_1 - B_2$

Here $B_1$ is the magnetic field due to the first wire which is mathematically represented as

$B_1 = \frac{\mu_o * I_1 }{2 \pi * d_1}$

Here $d_1$ is the distance to the half way point of the separation and the value is

$d_1 = 0.3 \ m$

$B_2$ is the magnetic field due to the first wire which is mathematically represented as

$B_2 = \frac{\mu_o * I_2 }{2 \pi * d_2}$

Here $d_2$ is the distance to the half way point of the separation and the value is

$d_2 = 0.3 \ m$

This means that $d_1 = d_2 = a = 0.3$

$B = \frac{\mu_o * I_1 }{2 \pi * d_1} - \frac{\mu_o * I_2 }{2 \pi * d_2}$

=> $B = \frac{\mu_o * (I_1 - I_2)}{2 \pi *0.3 }$

=> $B = \frac{ 4\pi * 10^{-7} * (9- 4)}{2 * 3.142 *0.3 }$

=> $B = 3.33 *10^{-6} \ T$

5 0

3 years ago

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

dedylja [7]

Answer:

Magnitude of net force will be 432.758 N

Explanation:

We have given x component of acceleration $a_x=760m/sec^2$

And vertical component of acceleration $a_y=770m/sec^2$

Mass of the ball m = 0.40 kg

So net acceleration $a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2$

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

3 0

3 years ago

If the distance between us and a star is doubled, with everything else remaining the same, the luminosity Group of answer choice

Savatey [412]

Answer:

remains the same, but the apparent brightness is decreased by a factor of four.

Explanation:

A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.

It is typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He).

The luminosity of a star refers to the total amount of light radiated by the star per second and it is measured in watts (w).

The apparent brightness of a star is a measure of the rate at which radiated energy from a star reaches an observer on Earth per square meter per second.

The apparent brightness of a star is measured in watts per square meter.

If the distance between us (humans) and a star is doubled, with everything else remaining the same, the luminosity remains the same, but the apparent brightness is decreased by a factor of four (4).

Some of the examples of stars are;

- Canopus.

- Sun (closest to the Earth)

- Betelgeuse.

- Antares.

- Vega.

8 0

3 years ago