Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) what is the electric
1 answer:
The expression for the magnitude of the electric field between two uniform conducting plates is
Here, V is potential difference between plates and d is separation between plates.
As the potential 6.00 cm from the zero volt plate (and 4.00 cm from the other) is 420 V.
Therefore,
Thus, the electric field strength between the plates is 7000 V/ m
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Answer:
Explanation:
Given that,
Current, I = 2 A
Voltage across the resistor, V = 18 V
We need to find the value of resistance of the resistor. Let the resistance be R. We can find it using Ohm's law i.e.
V = IR
Where
R is the resistance of the resistor
So, the resistance of the resistor is equal to .
To solve this problem we will use the trigonometric concepts to find the distance h, which will allow us to find the speed of Jeff and that will finally be the variable that will indicate the total tension, since it is the variable of the centrifugal Force given in the vine at the lowest poing of the swing.
From the image:
When Jeff reaches his lowest point his potential energy is converted to kinetic energy
Tension in the string at the lowest point is sum of weight of Jeff and the his centripetal force
Therefore the tension in the vine at the lowest point of the swing is 842.49N
