Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m=
=
m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
![X=u[2y/a]^{1/2}](https://tex.z-dn.net/?f=X%3Du%5B2y%2Fa%5D%5E%7B1%2F2%7D)
=![4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}](https://tex.z-dn.net/?f=4%2A10%5E6%5B2%2A2%2A10%5E%7B-2%7D%2F7%2A10%5E%7B14%7D%5D%5E%7B1%2F2%7D)
=
= 3 cm
Answer:
What will be the increase in frequency if these waves are reflected = 2979.63Hz
Explanation:
The detailed steps and appropriate formula is as shown in the attached file.
Answer:
b
Explanation:
i took the quiz i think its right
Your answer would be the letter B.)
:)
The step missing is after the number 4. Because, after the antenna captures de modultates waves, it has to be demodulated in order to be able to the signal be heard, seen or used.
So, the answer is that waves are demodulated and it before the signal is heard, seen or used.