Sound source A is located at x = 0, y = 0, and sound source B is located at x = 0, y = 2.3 m. The two sources radiate coherently
and in phase. An observer at x = 17.8 m, y = 0 notes that as he takes a few steps from y = 0 in either the +y or −y direction, the sound intensity increases. What is then the lowest frequency and next to lowest frequency of the sources that can account for this observation? (Enter your answers from smallest to largest.)
1 answer:
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Answer:
The magnitude of electron acceleration is
Explanation:
Given:
Distance from the wire to the field point m
Speed of electron
Current A
For finding the acceleration,
First find the magnetic field due to wire,
Where
T
The magnetic force exerted on the electron passing through straight wire,
N
From the newton's second law
Where mass of electron
kg
So acceleration is given by,
Therefore, the magnitude of electron acceleration is