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NeTakaya
3 years ago
12

A natural resource that is in limited supply is known as a _________________.

Physics
2 answers:
goblinko [34]3 years ago
6 0

Answer:

Limited Resources

PolarNik [594]3 years ago
4 0

Answer:I’m sure it lime red resources

Explanation:

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Suppose you have an unknown clear substance immersed in water, and you wish to identify it by finding its index of refraction. Y
jek_recluse [69]

When light passes from one medium to another at an angle, it may refract, or bend, according to Snell's law:

n₁sin(θ₁) = n₂sin(θ₂)

n₁ = index of first medium, θ₁ = angle of incidence, n₂ = index of second medium, θ₂ = angle of refraction

Given values:

n₁ = 1.33 (water), θ₁ = 45.0°, θ₂ = 40.3°

Plug in and solve for n₂:

1.33sin(45.0°) = n₂sin(40.3°)

n₂ = 1.454

I looked up this value on the HyperPhysics indices of refraction table... The index we calculated is closest to 1.46, which is that of fused quartz.

8 0
3 years ago
Two spheres A and B of negligible dimensions and masses 1 kg and √3 kg respectively, are supported on the smooth circular surfac
alexdok [17]

Answer:

α = π/3

β = π/6

Explanation:

Use arc length equation to find the sum of the angles.

s = rθ

π/20 m = (0.1 m) (α + β)

π/2 = α + β

Draw a free body diagram for each sphere.  Both spheres have three forces acting on them:

Weight force mg pulling down,

Normal force N pushing perpendicular to the surface,

and tension force T pulling tangential to the surface.

Sum of forces on A in the tangential direction:

∑F = ma

T − m₁g sin α = 0

T = m₁g sin α

Sum of forces on B in the tangential direction:

∑F = ma

T − m₂g sin β = 0

T = m₂g sin β

Substituting:

m₁g sin α = m₂g sin β

m₁ sin α = m₂ sin β

(1 kg) sin α = (√3 kg) sin (π/2 − α)

1 sin α = √3 cos α

tan α = √3

α = π/3

β = π/6

4 0
4 years ago
Two long conducting cylindrical shells are coaxial and have radii of 20 mm and 80 mm. The electric potential of the inner conduc
romanna [79]

Answer:

a) The speed of the electron as it reaches the inner conductor is closest to:

v = 1.45 × 10⁷m/s

b) The electric field magnitude between the cylinders is

E = 10,000V/m

Explanation:

given

inner radius of the cylinder r₁ = 20mm = 0.02m

outter radius of the cylinder r₂ = 80mm = 0.08m

potential difference V= 600V

mass of electron = 9.1×10⁻³¹kg

charge on electron = 1.6×10⁻¹⁹C

calculating the work done in bringing electron at inner conductor is

W =\frac{1}{2}mv^{2}

note:

V = \frac{W}{q}

∴W = (ΔV)q

(ΔV)q = \frac{1}{2}mv^{2}

(600)1.6×10⁻¹⁹ = ¹/₂ × 9.1×10⁻³¹ × v²

v² ≈ 2.11 × 10¹⁴

v = 1.45 × 10⁷m/s

According to the energy conservation law, the total energy of an isolated system is always constant.  

The energy of an isolated system can neither be created nor be destroyed, it can only convert one form to another form.

∴ the maximum electric field

E = ΔV/d

E = 600/d

where d is the distance between the two points

where d = 0.06m

E = 600/0.06

E = 10,000V/m

Note: the electric field due to the potential difference between to points depends upon the potential difference V and the distance between both points d.

5 0
3 years ago
What services can you expect from a personal trainer?
ludmilkaskok [199]

Answer:

You answered your own question, I'm confused about what you're asking for.

3 0
3 years ago
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The meeting in orbit of two or more spacecraft is A. orbital countermand. B. orbital farce. C. orbital hit. D. orbital rendezvou
k0ka [10]
<span> D. orbital rendezvous</span>
6 0
3 years ago
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