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Mariulka [41]
3 years ago
13

When a loose brick is resting on a wall, it has energy. When the brick is pushed off the wall and is falling down, the amount of

energy is decreasing while the amount of energy is increasing.
Physics
2 answers:
alukav5142 [94]3 years ago
7 0

The complete sentence is as follows:

When a loose brick is resting on a wall, it has potential energy. When the brick is pushed off the wall and is falling down, the amount of potential energy is decreasing while the amount of kinetic energy is increasing.

Explanation:

- Potential energy is the energy related to the position of an object: in particular, gravitational potential energy is given by

U=mgh

where m is the mass of the object, g is the gravitational acceleration, and h is the height of the object above the ground.

- Kinetic energy is the energy related to the motion of an object, and it is given by

K=\frac{1}{2}mv^2

where m is the mass and v the speed of the object.


In the example, we see that:

- at the beginning, the brick is at rest on the wall, so it only has potential energy due to its height above the ground (while the kinetic energy is zero, since it is at rest, so speed v is zero)

- as it falls down, the potential energy decreases, because the height h decreases, while the kinetic energy increases, because the speed of the object increases as it falls down.

OLga [1]3 years ago
5 0
Potential
Potential
Kinetic
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Someone please help ! this is worth 40 points!!
makvit [3.9K]

Explanation:

  1. non uniform motion
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5 0
2 years ago
If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h
raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory (u_x) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

u^2=u_x^2+u_y^2

Where, u_x\ and\ u_y are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1

Now, we know that, for a projectile motion, the maximum height is given as:

H=\frac{u_y^2}{2g}

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m

Therefore, the maximum height reached is 4.63 m.

3 0
3 years ago
Select the correct location on the image.<br> Identify the magnetic north pole of Earth’s magnet.
OverLord2011 [107]

The magnetic north pole of the earth's magnet is in the geographic south pole.

  • There are two magnetic and geographic poles each, north and south
  • The two geographic poles are the locations where the earth's axis of rotation passes through which is imaginary
  • The magnetic north and south poles are not the same as the geographic north and south poles
  • In a compass, the needle points to the magnetic north pole
  • By convention, the magnetic north pole corresponds to the geographic south pole
  • The magnetic south pole corresponds to the geographic north pole
  • The magnetic field lines of a magnet start from the magnetic north pole and end at the magnetic south pole

The magnetic north pole of the earth's magnet is the geographic south pole.

Learn more about earth's magnetism here:

brainly.com/question/3928159

#SPJ10

8 0
2 years ago
An air bubble has a volume of 2.0 cm3 when it is released by a submarine 100 m below the surface of a freshwater lake. What is t
UkoKoshka [18]

Answer:

21.35 cm^3

Explanation:

let the volume at the surface of fresh water is V.

The volume at a depth of 100 m is V' = 2 cm^3

temperature remains constant.

density of water, d = 1000 kg/m^3

Pressure at the surface of fresh water is atmospheric pressure,

P = Po = 1.013 x 10^5 N/m^2

The pressure at depth 100 m is P' = Po + hdg

P' = 1.013 \times 10^{5}+ 100 \times 1000 \times 9.8

P' = 10.813 x 10^5 N/m^2

Use the Boyle's law

P V = P' V'

1.013 \times 10^{5}\times V = 10.813 \times 10^{5}\times 2

V = 21.35 cm^3

Thus, the volume of air bubble at the surface of fresh water is 21.35 cm^3.

5 0
3 years ago
20 points+ Brainliest
Helen [10]

Answer:

The answer is B. hope this helps

Explanation:

3 0
3 years ago
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