Answer:
140265.8 C = 1.403 × 10⁵ C
Explanation:
The battery's electric potential energy is used to account for the kinetic and potential work done in moving the car up this hill.
Potential work required to move the 757 kg car up a vertical height of 195 m = mgh
P.E = 757 × 9.8 × 195 = 1446627 J
Kinetic work done = (1/2)(m)(v²)
K.E = (1/2)(757)(25²) = 236562.5 J
Total work done in moving the car up that height = 1446627 + 236562.5 = 1683189.5 J
And this would be equal to the potential of the battery.
For the battery, potential difference = (electric potential energy)/(charges moved)
ΔV = ΔU/q
q = ΔU/ΔV
ΔU = 1683189.5 J
ΔV = 12.0 V
q = 1683189.5/12 = 140265.8 C
You would have to pick the word c because that is the answer
Answer:
A ( Jack did twice as much work as Jill
Explanation:
Answer:
m = 2,776.95 kg
Explanation:
given,
radius = 1.5 m
mass = 1.19 x 10⁴ Kg
constant speed, v = 1.4 m/s
Resistive force = 1105 N
density of sea water = 1.03 x 10³ kg/m³
Volume of vessel,
v = 14.14 m³
Upthrust,
U = ρ g V
U = 1030 x 9.8 x 14.14
U = 142729.16 N
Since the vessel is moving at a constant speed, the resultant force on it should equal zero.
downward acting forces = upward acting forces
Mg = U + resistive force
M x 9.8 = (142729.16+1105)
M=14676.95 Kg
Mass of water,
m = M - mass of vessel
m = 14676.95 Kg- 11,900 kg
m = 2,776.95 kg
