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Rzqust [24]
3 years ago
11

How do objects move under the influence of gravity?

Physics
1 answer:
Nady [450]3 years ago
4 0

Under the influence of gravity, objects just move down to the earth.

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

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a motorcycle accelerates from 15 m/s to 20 m/s over a distance of 50 meters. what is its average acceleration?
devlian [24]
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s² So the average acceleration is 1.75 m/s²
5 0
3 years ago
Why is weathering slow in cold, dry places?
Alexxandr [17]

Rate of weathering depends on temperature and moisture. Cold dry places have less water to weather things


Hope this helped!

Don't forget: Mark Brainliest!

Have a good day :)

6 0
3 years ago
The use of drugs to treat disease is called?
Mila [183]
The use of drugs to treat disease is called medication
5 0
3 years ago
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if bananas are curved because they grow towards the sun ☀️so say if a was born towards the sun would i have been a curved baby o
Ivenika [448]

ಠ_ಠ Hey, hang on.. you might've made a discovery. Nobody has tested it so how do we know? ಠ_ಠ

3 0
3 years ago
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It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
Elena-2011 [213]

Answer:

B) the change in momentum.

Explanation:

The impulse is defined as the product between the force applied on an object (F) and the duration of the collision (\Delta t):

J=F \Delta t (1)

We can rewrite the force by using Newton's second law, as the product between mass (m) and acceleration (a):

F=ma

So, (1) becomes

J=ma \Delta t

Now we can also rewrite the acceleration as ratio between the change in velocity and change in time: a=\frac{\Delta v}{\Delta t}. If we substitute into the previous equation, we find

J=m\frac{\Delta v}{\Delta t}\Delta t=m\Delta v

And the quantity m\Delta v is equivalent to the change in momentum, \Delta p.

6 0
3 years ago
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