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ludmilkaskok [199]
2 years ago
12

A 50 n force is acting on a lever 1.5 m from the fulcrum balances an object 1m from the fulcrum on the other arm. what is the we

ight of the object in n and what is the mass in kg​
Physics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

Answer:

A 100 N force acting on a lever 2 m from the fulcrum balances an object 0.5 m from the fulcrum on. ... What is the weight of the object(in newtons)? What is its mass (in kg)? ... mass at the one end and effort arm is the distance between pivot and effort applied at the other end.

Explanation:

hpoe this helps you.

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The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate
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It would take approximately 289 hours for the population to double

Explanation:

Recall the expression for the continuous exponential growth of a population:

N(t)=N_0\,e^{kt}

where N(t) measures the number of individuals, No is the original population, "k" is the percent rate of growth, and "t" is the time elapsed.

In our case, we don't know No (original population, but know that we want it to double in a certain elapsed "t". We also have in mind that the percent rate "k" would be expressed in mathematical form as: 0.0024 (mathematical form of the given percent growth rate).

So we need to solve for "t" in the following equation:

2\,N_0=N_0\,e^{0.0024\,t}\\\frac{2\,N_0}{N_0} =e^{0.0024\,t}\\2=e^{0.0024\,t}\\ln(2)=0.0024\,t\\t=\frac{ln(2)}{0.0024} \\t=288.811\,\, hours

Which can be rounded to about 289 hours

6 0
3 years ago
In a track and field event, a hammer thrower accelerates the hammer (mass = 7.30 kg) from rest within four full turns (revolutio
lubasha [3.4K]

Answer:

5.69755 rad/s²

Explanation:

r = Radius = 1.3 m

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n = Number of revolutions = 4

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\theta=n\times 2\pi\\\Rightarrow \theta=4\times 2\pi\\\Rightarrow \theta=8\pi

\omega_i = Initial angular speed = 0

Final angular speed

\omega_f=\frac{v}{r}\\\Rightarrow \omega_f=\frac{22}{1.3}\\\Rightarrow \omega_f=16.92307\ rad/s

Angular acceleration

\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{16.92307^2-0^2}{2\times 8\pi}\\\Rightarrow \alpha=5.69755\ rad/s^2

Angular acceleration is given by 5.69755 rad/s²

3 0
3 years ago
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