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ella [17]
3 years ago
15

In a zoo there are zebras and peacocks sharing the same area. There is a total of 14 zebras and peacocks. If you count, there is

also a total of 36 legs. How many of each animal are there ? (15 Points & brainliest answer to the first person !) thanks :)
Mathematics
1 answer:
Arturiano [62]3 years ago
3 0
If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs, 
Therefore the total number of legs will be 4x + 2y  which is equal to 36 .
Therefore, we have two equations 
    x + y = 14
   4x + 2y = 36    solving them simultaneously using elimination
   
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
     2x = 8 ( subtracting the equations)
        x = 4  
       y = 14 -(4) 
          = 10
Therefore, there are 4 zebras and 10 peacocks in the zoo
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