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nydimaria [60]
3 years ago
14

Is aluminum flammable

Chemistry
2 answers:
konstantin123 [22]3 years ago
5 0

Answer:

aluminum powder is flammable

Explanation:

VashaNatasha [74]3 years ago
3 0
Yes, aluminum is flammable
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Question 10 (1 point)
Vinil7 [7]

Answer:

A,C,D,B

Explanation:

1killometer=1000m

1mm=0.001m

1cm=0.01m

base unit of length is meter

7 0
3 years ago
What are the bad side effects of multitasking?<br> 2-4 sentences pleaze
Reil [10]

Answer:

Today, the vast majority of us multitask while using our smartphones. We play games, email, surf social media, text, and use apps and other functions while watching television, eating, doing work, or while "engaged" in a conversation with another person. Multitasking has become such a regular part of our lives that most of us believe we do it well—and few imagine it could actually be dangerous.

Explanation:

1. Multitasking is associated with harm to our brains.

2. Multitasking can lead to memory problems.

3. Multitasking can lead to increased distractibility.

4. Multitasking can make us walk into traffic.

5. Multitasking hurts your grades and the grades of those around you.

6. Multitasking can lead to falling and breaking bones.

7. Multitasking can harm your relationship.

8. Multitasking increases chronic stress.

9. Multitasking increases depression and social anxiety.

10. Multitasking makes you less productive and less efficient.

6 0
3 years ago
100 points!!!!!!!!!!!!!!!!!! how does a volcanic eruption benefit the surrounding area? A. Lava and ash bury animal habitats. B.
Shkiper50 [21]
I think it would be C) The surrounding soil can become very fertile

4 0
3 years ago
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What is frequency a measure of ?
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Frequency is a measure of hertz
6 0
3 years ago
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A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
4 years ago
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