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Natalija [7]
3 years ago
14

Andy is entering early adolescence. although he used to be a big help to his mother by doing household chores, he now refuses, s

aying that the chores are "women's jobs." he also has a new interest in competitive sports and is being assertive in his interactions with friends. andy is most likely experiencing
a. gender intensification.
b. gender segregation.
c. gender typing.
d. the timing of puberty effect
Physics
1 answer:
o-na [289]3 years ago
8 0

Answer:

a. gender intensification

Explanation:

This theory states that in the adolescence both girls and boys are pressured to follow gender roles established culturally.

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6. (a) Suppose the earth is revolving round the sun in a circular orbit of radius one b astronomical unit (1.5% 10 km). Find the
kkurt [141]

Answer:

tough

ques

Explanation:

5 0
2 years ago
With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s
Dima020 [189]
  • initial velocity=u=20km/h=5.5m/s
  • Acceleration=a=8m/s^2
  • Time=t=10s

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2

\\ \sf\longmapsto s=55+4(5.5)^2

\\ \sf\longmapsto s=55+4(30.25)

\\ \sf\longmapsto s=55+121

\\ \sf\longmapsto s=176m

4 0
3 years ago
What activity would require more impulse?
Gnesinka [82]

B. Accelerating a bowling ball from rest to 35 m/s

Explanation:

Accelerating a bowling ball from rest to 35m/s will require more impulse compared to a baseball.

Impulse is the force acting on a body a particular period of time. It is similar to momentum.

When impulse is applied on a body, it change it state from rest and cause motion.

A body with more mass will require a higher impulse to cause it to accelerate. Bowling balls are heavier. They require more impulse to make them move.

Learn more:

Momentum brainly.com/question/9484203

#learnwithBrainly

3 0
3 years ago
A sphere of radius 5.15 cm and uniform surface charge density +12.1 µC/m2 exerts an electrostatic force of magnitude 35.9 ✕ 10-3
rosijanka [135]
The radius of the sphere is r=5.15 cm=0.0515 m, and its surface is given by
A=4 \pi r^2 = 4 \pi (0.0515 m)^2 = 0.033 m^2

So the total charge on the surface of the sphere is, using the charge density 
\rho=+1.21  \mu C/m^2 = +1.21 \cdot 10^{-6} C/m^2:
Q= \rho A = (+1.21 \cdot 10^{-6} C/m^2)(0.033 m^2)=4.03 \cdot 10^{-8}C

The electrostatic force between the sphere and the point charge is:
F=k_e  \frac{Qq}{r^2}
where
ke is the Coulomb's constant
Q is the charge on the sphere
q=+1.75 \muC = +1.75 \cdot 10^{-6}C is the point charge
r is their separation

Re-arranging the equation, we can find the separation between the sphere and the point charge:
r=\sqrt{ \frac{k_e Q q}{F} }= \sqrt{ \frac{(8.99 \cdot 10^9 Nm^2 C^{-2})(4.03 \cdot 10^{-8} C)(1.75 \cdot 10^{-6}C)}{35.9 \cdot 10^{-3}N} }=0.133 m=13.3 cm
8 0
3 years ago
How many photons are absorbed during the dental x-ray?
MariettaO [177]
<span>E=hc/wav. len
E = (6.62 x 10^-34 x 3 x 10^8)/0.0275 x 10^-9
E = 7.22182 x 10^-15 J
To convert to eV divide by 1.6 x 10^-19
E = 7.22182 x 10^-15/1.6 x 10^-19 eV
E =45.36 x 10^3 eV
Th energy, E, of a single x-ray photon in eV is = 45.36keV.

Number of photons, n = total energy/ energy of photon
n = 3.85 x 10^-6/7.22182 x 10^-15
n = 5.33 x 10^8 photons </span>
8 0
3 years ago
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