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Morgarella [4.7K]

3 years ago

11

How much work (in J) is involved in a chemical reaction if the volume decreases from 5.35 to 1.55 L against a constant pressure

of 0.829 atm?

1 answer:

Mrac [35]3 years ago

5 0

Answer:- work = 319 J

Solution:- The volume of the gas decreases from 5.35 L to 1.55 L.

$\Delta V=1.55L-5.35L$ = -3.80 L

external pressure is given as 0.829 atm.

$w=-P_e_x_t\Delta V$

where w is representing work.

Let's plug in the values and calculate pressure-volume work:

$w=-0.829atm(-3.80L)$

w = 3.15 atm.L

We need to convert atm.L to J.

1 atm.L = 101.325 J

So, $3.15atm.L(\frac{101.325J}{1atm.L})$

= 319 J

So, 319 J of work is involved in a chemical reaction. Positive work means the work is done on the system.

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