11,000 - rounded to the nearest thousand!
let t = time (hrs) that they are 50 mi apart
Use pythag here; a^2 + b^2 = c^2; dist = speed * time
(30t)^2 (40t)^2 = 50^2
900t^2 + 1600t^2 = 2500
It's obvious that t = 1 hr
Answer:
6
Step-by-step explanation:
2 + (1/10)(1/5)(1/10)2000 = 2 + (1/500)(2000) = 2 + 4 = 6
x + (x + 3) + 
= 75
so you will add up all of the x 's but NOT the x^2
2x + 3 + = 75
Rearrange to put the x^2 in front of 2x
+ 2x + 3 = 75
subtract the 75 from both sides
+ 2x - 72 = 0
