Answer:
His walks cover 2km+2km+2km = 6 km.
Explanation:
Let East be positive. Since West is the opposite direction, it is negative. His displacement is dependent on direction. 2km east + 2km west + 2km east = (2-2+2)km = 2km. His displacement is 0 because he ends up back where he started.
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Answer:
Part a)
F = 14.4 N
Part b)
away from +6μC charge
Explanation:
Force on the charge placed midway between two charges is given by
here we know that
here the charge is placed at mid point so we have
now we have
Part b)
since +6μC charge is more in magnitude so the force due to this charge will be more so the net force on it is away from +6μC charge
Your answer is D Flammability
If time (t), acceleration(a) and initial velocity (Vi) is given distance can be find by
S = (Vi)t + (1/2) at²
If both velocities initial velocity an final velocity is given then formula will be
2aS = (Vf)²- (Vi²)
Where S is the distance.