The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.
<h3>Impulse experienced by objects</h3>
The impulse experienced by any object is equal to the change in the momentum of the object.
The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.
J = Ft
where;
- F is applied force = 8000 N
- t is time, = 1.1 ms
J = (8000) x (1.1 x 10⁻³)
J = 8.8 Ns
Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.
Learn more about impulse here: brainly.com/question/229647
Answer:
Frequency = 260 Hz and wavelength = 1.31 m
Explanation:
Given that,
A hammer begins vibrating back and forth at approximately 260 cycles per second.
(a) The frequency of an object is the number of vibrations per unit time. The frequency of the sound wave is 260 Hz.
(b) The speed of sound in air is 343 m/s. So,

Hence, this is the required solution.
Answer:
(b) In ideal condition we neglect mass of spring but in real springs mass of spring adds another factor to its time period.
since we are adding a factor of mass to the system, and frequency being inversely proportional to squared root of mass, we can come to a general conclusion that it effectively reduces the natural frequency .
Explanation:
kindly check the attachment for explanation.
Answer:
Gas like oxygen, nitrogen etc