How much tension must a rope withstand if used to accelerate a 960-kg car from rest horizontally along a frictionless surface to 1.20 m/s in 5 seconds?
1 answer:
Use a=(dv/dt) (change in velocity/ change in time)=acceleration (1.2/5)=acceleration F=ma (Newton's second law, Force= Mass x Acceleration =960 x 0.24 F=230.4N If T<230.4N then the tow rope will hold
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