<u>Answer:</u> The number of phosphorus atoms in given amount of copper(II) phosphate is 
<u>Explanation:</u>
We are given:
Moles of copper(II) phosphate
= 7.00 mol
1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms
Moles of phosphorus in copper(II) phosphate = 
According to the mole concept:
1 mole of a compound contains
number of particles
So, 7.00 moles of copper(II) phosphate will contain =
number of phosphorus atoms.
Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is 
Answer:
3.5 mol KClO3
Explanation:
Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.
x mole of KClO3 = 3.5 mol KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3
x mole of KClO3 = 3.5 mol KClO3
Below is the structure of 3-Methylpentane. The word pentane in name specifies the parent chain which ends on -ane (alkane) and pent- shows number of carbon atoms is parent chain (pent=5). The position of substituent is specified at the start i.e. 3.
Answer:
See figure 1
Explanation:
We have to remember that in the isomer structures we have to <u>change the structure</u> but we have to maintain the <u>same formula</u>, in this case
.
In the formula, we have 1 nitrogen atom. Therefore we will have as a main functional group the <u>amine group</u>.
In the amines, we have different types of amines. Depending on the number of carbons bonded to the "N" atom. In the <em>primary amines</em>, we have only 1 C-H. In the <em>secondary amines</em>, we have two C-N bonds and in the <em>tertiary amines</em>, we have three C-N bonds.
With this in mind, we can have:
-) <u>Primary amines:</u>
1) n-butyl amine
2) sec-butyl amine including 2 optical isomers
3) isobutyl amine
4) tert-butyl amine
-) <u>Secondary amines:</u>
5) N-methyl n-propyl amine
6) N-methyl isopropyl amine
7) N, N-diethyl amine
-) <u>Tertiary amines:</u>
8) N-ethyl N, N-dimethyl amine
See figure 1
I hope it helps!