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DanielleElmas [232]
2 years ago
5

4. Consider the following reaction:

Chemistry
1 answer:
Lyrx [107]2 years ago
4 0

Answer:

High temperatures

Explanation:

NaHCO₃ (8) + HCH,O₂ (aq) → H₂O (l) + CO₂ (g) + NaC,H₃O₂ (aq)

As the flask gets cooler to the touch as the reaction proceeds, the reaction is endothermic. This means that ΔH is positive (ΔH>0).

As a gas is formed (bubbles are formed), ΔS is positive (ΔS>0).

<em>In terms of ΔG:</em>

  • ΔG = ΔH - TΔS

<em>In order for the reaction to be thermodynamically favorable, ΔH has to be negative</em>, thus:

  • The reaction is favorable if TΔS > ΔH.

The greater the temperature, the easier it would be for TΔS to be greater than ΔH.

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sineoko [7]
You can separate a mixture of salt and sand by...

First combing the mixture with water and mix thoroughly until the salt dissolves..

Then you could let the sand settle at the bottom of the salt water, so you can strain salt water to separate the sand from salt water...

To get salt... you would heat up the water to let it evaporate. When all the water is evaporated, the salt will be left behind
3 0
3 years ago
A 50.0-gram block of copper at 10.0°C is carefully lowered into 100.0 grams of water at 90.0°C in an insulated container. Which
Andrei [34K]
First consider and take note of the following: 
1. When 2 or more finite amounts of substances are mix together (with different temperature) the final temperature is never equivalent to the initial temperature of any of the substances involved. 
2. The substances meet at an equilibrium temperature. 
3. Heat transfers from a higher temperature to a lower temperature. 

Only choice (3) satisfies the conditions. 
5 0
3 years ago
6. 100 ml of gaseous hydrocarbon consumes 300
mario62 [17]

Answer:

  • <u><em>a. C₂H₄</em></u>

Explanation:

At constant pressure and temperature, the mole ratio of the gases is equal to their volume ratio (a consequence of Avogadro's law).

Hence, the <em>complete combustion reaction</em> that has a ratio of 100 ml of gaseous hydrocarbon to 300 ml of oxygen, is that whose mole ratio is 1 mol hydrocarbon : 3 mol of oxygen.

Then, you must write the balanced chemical equations for the complete combustion of the four hydrocarbons in the list of choices, and conclude which has such mole ratio (1 mol hydrocarbon : 3 mol oxygen).

A complete combustion reaction of a hydrocarbon is the reaction with oxygen that produces CO₂ and H₂O, along with the release of heat and light.

<u>a. C₂H₄:</u>

  • C₂H₄ (g) + 3O₂ (g) → 2CO₂(g)  + 2H₂O (g)

Precisely, for this reaction the mole ratio is 1 mol C₂H₄: 2 mol O₂, hence, this is the right choice.

The following analysis just shows that the other options are not right.

<u>b. C₂H₂:</u>

  • 2C₂H₂ (g) + 5O₂ (g) → 4CO₂(g)  + 2H₂O (g)

The mole ratio for this reaction is 2 mol C₂H₂ :5 mol O₂.

<u>с. С₃Н₈</u>

  • C₃H₈ (g) + 5O₂ (g) → 3CO₂(g)  + 4H₂O (g)

The mole ratio is 1 mol C₃H₈ : 5 mol O₂

<u>d. C₂H₆</u>

  • 2C₂H₆ (g) +7 O₂ (g) → 4CO₂(g)  + 6H₂O (g)

The mole ratio is 2 mol C₂H₆ : 7 mol O₂

7 0
3 years ago
An isotope of lead can be represented by the following symbol ²⁰⁷ 82 PB. From this symbol, it can be deduced that one atom of th
9966 [12]

Answer:

B) 82 protons

Explanation:

The number of protons for an element never change. 82 Is the atomic number for Pb which is how many protons it has. An isotope means it has more neutrons.

6 0
3 years ago
Please I need help with questions 1-4 and can you check if I plot it correct in to the punnet square for questions 1-4 and I nee
fgiga [73]
Number 1 is incorrect, the genotypes are given to you. You need to use GG and gg. The outcome would be 100% Gg.

Number 2 is incorrect, the genotypes are given to you. You need to use Gg and Gg. The outcome would be 25% gg, 25% GG, and 50% Gg.

Number 3 is incorrect, the genotypes are given to you. You need to use TT and tt. The outcome would be 100% Tt.

Number 4 is incorrect, the genotypes are given to you. You need to use RR and rr. The outcome would be 100% Rr.

Please read the directions and use the genotypes they give you! The information is all there for you, you just need to put it in correctly. If you're still having trouble understanding how to do this, feel free to message me and I'd be happy to help you.
8 0
3 years ago
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