Question

4. Consider the following reaction:

Answer 1

Answer:

High temperatures

Explanation:

NaHCO₃ (8) + HCH,O₂ (aq) → H₂O (l) + CO₂ (g) + NaC,H₃O₂ (aq)

As the flask gets cooler to the touch as the reaction proceeds, the reaction is endothermic. This means that ΔH is positive (ΔH>0).

As a gas is formed (bubbles are formed), ΔS is positive (ΔS>0).

In terms of ΔG:

• ΔG = ΔH - TΔS

In order for the reaction to be thermodynamically favorable, ΔH has to be negative, thus:

• The reaction is favorable if TΔS > ΔH.

The greater the temperature, the easier it would be for TΔS to be greater than ΔH.