Answer:
the resultant velocity is Zero
Explanation:
by the rule of adding and subtracting factors, we know that; when the force acting on an object is from east & north we add and with forces acting from South & west we minus.
Therefore:
1) List the forces down:
the 100m/s acting west is (-) while
the other 100m/s is acting in easterly direction
so it is (+)
2) Add the forces:
-100+100=0
therefore the answer is 0m/s for the the resultant velocity
hope I'm right
Just a guess without asking Google, that without the sun's gravity holding us in orbit, we would end up drifting whatever direction we were headed as it disappeared?
Answer:
22.22m/s
Explanation:
The momentum before a collision = momentum after collision so...
work out the momentum of the first object (the bullet)
its p = mv
0.04 kg × 300 m/s = 0.54 kg × v
rearrange this to find v which is 0.04 x 300 = 12
so 12 = 0.54 x v
12/0.5 = v
v = 22.22m/s
hope this helps!
Answer:
Explanation:
The amplitude of resultant wave as the result of overlap of two waves depends upon the phase difference between the two. If the waves meet crest to trough , the phase difference is 180 degree or they are in opposite phase . Hence they will destroy each other . The amplitude of resultant wave can be obtained by subtracting the amplitudes of two waves. They will interfere destructively.
Amplitude of resultant gives waves = 4.6 - 2 = 2.6 cm.
Answer:
θ = 225 rad
Explanation:
given data
angle = 25 rad
to find out
angular velocity after 3t?
solution
let angular acceleration α in t
θ = ω × t + 0.5 × α × t² ........................1
here ω = 0 (initial velocity )
so put this value here
25 = 0 + 0.5 × α × t² ..........................2
α = 25 ÷ (0.5 t²)
α = 50 ÷ t² .........................3
now here we take in 3t
θ = ω × 3t + 0.5 × α × (3t)²
for ω = 0
θ = 0 + 0.5 × α × 9t²
now put value in eq 2
so
θ = (0.5) × (50 ÷ t²) × (3t)²
θ = 25 × 9
θ = 225 rad
