Answer:
1) 2.388ohms
2) R1 3.36A
R2 1.682A
R3 2.88A
R4 2.16A The current has 5.048A over all
3) Voltage in R1 is 3.36v
Voltage in R4 is 8.63v
Explanation:
1. Each of the resistance R1 and R2 are in parallel in series combination with R3 and R4 so we calculate
R1 and R2 which is 1×2÷(1+2)= 0.6667ohms
R3 and R4 which is 3×4÷( 3+4)= 1.71ohms
so the equivalent resistance is 0.667+ 1.71= *2.377ohms*
2. The overall current = voltage source ÷ total resistance
= 12÷ 2.377= 5.048Amps
so current in every resistor will be
current in 1ohms will be (2÷3)×5.048= 3.36Amps
current in 2ohms will be (1÷3)×5.048= 1.68Amps
current in 3ohms will be (4÷7)×5.048= 2.88amps
current in 4ohms will be (3÷7)× 5.048= 2.16amps
3. voltage in R1 is 0.667ohms × 5.048amps= 3.36v
voltage in R4 is 1.71ohms × 5.048amps= 8.63v
