Question

Starting from rest, a car travels 18 meters as it accelerates uniformly for 3.0 seconds. What is the magnitude of

Answer 1

Answer:

$a=4\frac{m}{s^2}$

Explanation:

Hello.

In this case, for this uniformly accelerated motion in which the car starts from rest at 0 m/s and travels 18 m in 3.0 s, we can compute the acceleration by using the following equation:

$x_f=x_0+v_0t+\frac{1}{2}at^2$

Whereas the final distance is 18 m, the initial distance is 0 m, the initial velocity is 0 m/s and the time is 3.0 s, that is why the acceleration turns out:

$a=\frac{2(x_f-v_ot)}{t^2} =\frac{2(18m-0m/s*3.0s)}{(3.0s)^2}\\ \\a=4\frac{m}{s^2}$

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