Answer:
116 N
Explanation:
Missing question: (found on google)
<em>"What is the force of the pitcher's hand on the 0.145 kg ball during this acceleration phase?
</em>
<em>Express your answer with the appropriate units."</em>
Solution:
First of all, we need to calculate the acceleration of the ball, given by
where
v = 40 m/s is the final velocity
u = 0 is the initial velocity
is the duration of the acceleration phase
Substituting,
Now we can find the force exerted on the ball by using Newton's second law:
where
m = 0.145 kg is the mass of the ball
a is the acceleration
Substituting,
F=ma which is newtons second law. so we have here a=g in this situation and g=gravity and that equals 9.80m/s^2 on earth surface. So we have F=5.7kg*9.80m/s^2=55.9N or Newtons. Thank You! Please rate!
The motion of objects w mass n velocity.
Answer:
The time it will take for the object to hit the ground will be 4.
Explanation:
You have:
h(t)=−16t²+v0*t+h0
Being v0 the initial velocity (54 ft/s) and h0 the initial height (40 ft) and replacing you get:
h(t)=−16t²+54*t+40
To know how long it will take for the object to touch the ground, the height h(t) must be zero. So:
0=−16t²+54*t+40
Being a quadratic function or parabola: f (x) = a*x² + b*x + c, the roots or zeros of the quadratic function are those values of x for which the expression is 0. Graphically, the roots correspond to the points where the parabola intersects the x axis. To calculate the roots the expression is used:
In this case you have that:
Replacing in the expression of the calculation of roots you get:
Expresion (A)
and
Expresion (B)
Solving the Expresion (A):
Solving the Expresion (B):
These results indicate the time it will take for the object to hit the ground can be -5/8 and 4. Since the time cannot be negative, then <u><em>the time it will take for the object to hit the ground will be 4.</em></u>