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svetoff [14.1K]

3 years ago

13

Which of the following solutions is the most acidic?

1 answer:

grandymaker [24]3 years ago

6 0

Answer:

i thin its a solution with the pH of 3

Explanation:

i don't understand the third choice

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Is the planet Uranus surface rocky or flat?

klemol [59]

Uranus is said to be made of fluids. Its atmosphere is its surface

6 0

3 years ago

What are the characteristics of an extrusive rock

olya-2409 [2.1K]

Extrusive Rocks. Igneous rocks which form by the crystallization of magma at the surface of the Earth are called extrusive rocks. They are characterized by fine-grained textures because their rapid cooling at or near the surface did not provide enough time for large crystals to grow.

5 0

3 years ago

An atom of sodium-23 (Na-23) has a net charge of

maksim [4K]

Answer:

Protons= 11

neutrons= 12

electrons = 10

Explanantion:

Look for Na on periodic table

Atomic Number = 11

Atomic Mass = 23 (round it to be an integer)

Number of protons = Atomic number = 11

Number of neutrons = Atomic mass - atomic number = 23-11 =12

Number of electrons = 11 - e = ´+1 , electrons = 10

6 0

2 years ago

A solution contains 0.021 M Cl and 0.017 M I. A solution containing copper (I) ions is added to selectively precipitate one of t

lidiya [134]

<u>Answer:</u> Copper (I) iodide will precipitate first.

<u>Explanation:</u>

We are given:

$K_{sp}$ of CuCl = $1.0\times 10^{-6}$

$K_{sp}$ of CuI = $5.1\times 10^{-12}$

Concentration of $Cl^-\text{ ion}=0.021M$

Concentration of $I^-\text{ ion}=0.017M$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

<u>For CuCl:</u>

$K_{sp}=[Cu^+][Cl^-]$

Putting values in above equation, we get:

$1.0\times 10^{-6}=[Cu^+]\times 0.021$

$[Cu^+]=\frac{1.0\times 10^{-6}}{0.021}=4.76\times 10^{-5}M$

Concentration of copper (I) ion = $4.76\times 10^{-5}M$

<u>For CuI:</u>

$K_{sp}=[Cu^+][I^-]$

Putting values in above equation, we get:

$5.1\times 10^{-12}=[Cu^+]\times 0.017$

$[Cu^+]=\frac{5.1\times 10^{-12}}{0.017}=3.00\times 10^{-10}M$

Concentration of copper (I) ion = $3.00\times 10^{-10}M$

For the precipitation of copper (I) ions, we need less concentration of copper (I) ions. So, copper (I) iodide will precipitate first.

7 0

3 years ago

A 12.5L container of neon had a pressure change

Elan Coil [88]

Answer: V= 44. 6 L

Explanation: use Boyle's Law

P1V1 = P2V2

Derive to find V2:

V2 = P1V1 / P2

= 937.57 Pa( 12.5 L ) / 262.52 Pa

= 44.6 L

5 0

3 years ago