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natulia [17]
3 years ago
14

Calculate how many moles of silver nitrate (AgNO3) are in 1.35 L of a 4.25 M solution of silver

Chemistry
1 answer:
Svetach [21]3 years ago
3 0

Answer:

is

Explanation:

is

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Can someone please give me a simple equation on the mass of an isotope
frutty [35]
Mass 1 + %abundance of first isotope + Mass 2 + %abundance of second isotope
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This is RAM.
5 0
2 years ago
The solubility of acetanilide in hot water (5.5 g/100 ml at 100∘C) is not very great, and its solubility in cold water (0.53 g/
Olin [163]

Answer:

89.4%

Explanation:

Initially, there is 5.0 of the acetanilide in 100 mL of water, then the solution is chilled at 0ºC. The solubility represents the amount that the solvent (water) can dissolve of the solute (acetanilide). So, at 0ºC, 100 mL of water can dissolve till 0.53 g of the compound, the rest will precipitate and will be recovered.

So, the mass that is recovered is 5.0 - 0.53 = 4.47 g

The percent recovery is:

(4.47/5)x100% = 89.4%

8 0
3 years ago
SOLVE The density of a gas is 0.68 g/mL. What amount of space would 23.8 g of this gas occupy?
Contact [7]

Answer:

<h2>The answer is 35 mL</h2>

Explanation:

Density of a substance can be found by using the formula

Density(\rho) =  \frac{mass}{volume}

From the question we are finding the amount of space the gas will occupy that's the volume of the gas

Making volume the subject we have

volume =  \frac{mass}{Density}

From the question

mass = 23.8 g/mL

Density = 0.68 g/mL

Substitute the values into the above formula and solve

That's

volume =  \frac{23.8}{0.68}

We have the final answer as

<h3>35 mL</h3>

Hope this helps you

6 0
2 years ago
A + B + C → D + E
brilliants [131]
I believe it is B... because all balance equation are supposed to follow the law of conservation of mass

8 0
2 years ago
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What determines the amount of energy an electron has?
Natalka [10]

Answer:

The energy of an electron in many–electron atom is determined by both principal quantum number (n) and azimuthal quantum number (l)

8 0
3 years ago
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