Answer:
The mass of SO2 will be equal to the sum of the mass of S and O2.
Explanation:
This can be explained by the <em>Law of Conservation of Mass</em>. This law states that mass can neither be created nor destroyed. Knowing this, we can say that the reactants of a chemical reaction must be equal to the products.
In this case, the reactants Sulfur (S) and Oxygen (O2) must equal the mass of the product Sulfur Dioxide (SO2). Therefore, the statement <em>"The mass of SO2 will be equal to the sum of the mass of S and O2" </em>is correct.
Answer:
1. 58.5g/mol
2. 261g/mol
3. 158g/mol
4. 71g/mol
5. 44g/mol
Explanation:
The molar mass of a compound is the total mass of the sum of masses of all individual elements that make up the compound. First, we need to know the atomic masses of each element in a compound.
1. NaCl
Where; Na = 23, and Cl = 35.5
Molar mass of NaCl = 23 + 35.5
= 58.5g/mol
2. Ba(NO3)2:
Where; Ba = 137, N = 14, O = 16
Molar mass of Ba(NO3)2: 137 + {14 + 16(3)} 2
137 + (14 + 48)2
137 + (62)2
137 + 124
= 261g/mol
3. K(MnO4)
Where; K = 39, Mn = 55, O = 16
Molar mass of KMnO4 = 39 + 55 + 16(4)
= 94 + 64
= 158g/mol
4. Cl2
Where; Cl = 35.5
Molar mass of Cl2 = 35.5(2)
= 71g/mol
5. CO2
Where; C = 12, O = 16
Molar Mass of CO2 = 12 + 16(2)
= 12 + 32
= 44g/mol
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Answer:
Option B is correct. A nuclear alpha decay
Explanation:
Step 1
This equation is a nuclear reaction. So it can be an alpha decay or a beta decay
An α-particle is a helium nucleus. It contains 2 protons and 2 neutrons, for a mass number of 4.
During α-decay, an atomic nucleus emits an alpha particle. It transforms (or decays) into an atom with an atomic number 2 less and a mass number 4 less.
Thus, radium-226 decays through α-particle emission to form radon-222 according to the equation that is showed.
A Beta decay occurs when, in a nucleus with too many protons or too many neutrons, one of the protons or neutrons is transformed into the other.
Option B is correct. A nuclear alpha decay
Answer:
3.018 x 10⁻⁶ M.
Explanation:
- Co(OH)₂ dissociates in solution according to the equation:
<em>Co(OH)₂ →</em> <em>Co²⁺ + 2OH⁻.</em>
<em></em>
<em>∵ Ksp = [Co²⁺][OH⁻]² = (s)(2s)² = 4s³.</em>
<em />
∴ 4s³ = 1.10 x 10⁻¹⁶.
∴ s³ = 1.10 x 10⁻¹⁶/4 = 2.75 x 10⁻¹⁷.
∴ s = ∛(2.75 x 10⁻¹⁷) = 3.018 x 10⁻⁶ M.
